Page 57 - Fluid Power Engineering
P. 57

34    Cha pte r  T w o











               FIGURE 2.18  Single oil lump, subjected to oil compressibility.




                   Variation of volume of oil in line due to inlet and outlet flow
               rates, ΔV , is
                       Q
                                ΔV = (∑  Q −  ∑ Q ) dt              (2.58)
                                  Q ∫
                                          in
                                                 out
                   Variation of volume of oil in the line due to the compressibility
               effect, ΔV , is
                       c
                                               V
                                         ΔV =−   Δp                 (2.59)
                                           C
                                                B
                                          dV     V dP
               Then, referring to Eq. (2.48),    C  =−              (2.60)
                                           dt    B dt

                                   ΔV +  ΔV =  ΔV                   (2.61)
                                      Q    C    L

                   The variation of volume of line ΔV  depends on the line material,
                                                L
               wall thickness, diameter and system pressure: ΔV = (). Assuming
                                                            f P
                                                         L
               rigid wall boundaries, then ΔV = 0.
                                         L
                                     dV   dV
               or                      Q  +  C  = 0                 (2.62)
                                      dt   dt
                                   in ∑
                               ∑  Q −    Q out  −  B dt  = 0
               Then,                          V dP                  (2.63)

                   The application of Eq. (2.63) to the single lump flow in a pipe (see
               Fig. 2.18) yields

                                           V dP
                                   Q − Q −      =  0                (2.64)
                                    1   2  B dt
                           B
                                                     B
                                                 i ∫
                                 Q dt  or  P =
                                                           Q dt
               or     ΔP = ∫  V ( Q − )         P +  V ( Q − )      (2.65)
                                                            2
                               1
                                   2
                                                        1
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