Page 329 - Fluid-Structure Interactions Slender Structure and Axial Flow (Volume 1)
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310               SLENDER STRUCTURES AND AXIAL FLOW

                     Consider first the trivial equilibrium position, wo = 0, i.e. the origin {q, i) = (0, 01, in
                   which case we can use (5.82) rather than (5.88). The function
                                                              +
                                                     +
                                                                 {
                         H, = ;1,12   + ;{lw1/12 -  ~ 1 ~ ’ 1 ~ );4w’14   + (w, w)}     (5.89)
                                              ~
                                                                u
                   is a suitable Lyapunov function (Movchan 1965; Parks 1967), in which u is to be chosen
                   subsequently. It  is  noted that, essentially, (5.89) has the  form of  kinetic plus potential
                   energy  (the Hamiltonian), as  related to  (5.82); however, the  extraneous last  bracketed
                   term  is  essential  in  rendering Ha a  Lyapunov function.  To  prove  that  Ha is  positive
                   definite, we start with the inequality
                               Ha 2 ;1WI2  + ;{n41wl2 - u2n2lwI2} + iw{alw12 + (w, W)),   (5.90)

                   in which (a) the first of equations (5.87) is used to show that Iw”I2 = n21w’I2, and (b) the
                   fact that  I#I2   2 n219l2 for  any  continuous function with $(O)  = +(l) = 0 - as easily
                   ascertained for trigonometric functions. Then, re-writing lWI2 + 2u(w, W) = I(uw + W)I2 -
                   w21wI2, inequality (5.90) may be written as

                                  Ha p i[u(a - u) + n2(n2 u2)]1w12 + il(ww + W)I2,
                                                        ~
                   which  is  globally  positive definite provided  that  u < n and  0 5 w 5 a. Therefore, for
                   given u and u, as (lw’I2 + lW12}1/2  increases, so does Ha, monotonically.
                     Differentiating Ha with t and using (5.82) with q = w, and then applying the boundary
                   conditions in the resulting integrations by parts,
                                                                +
                        -- - -(a  - u)lWI2 + 2wB’/*u(w’, 6) - ~lw’’1~    - ;~.dlw’1~    (5.91)
                        ma
                        dt
                   is obtained. Then, making use of the inequality   ? n21@I2 again, this may be written as

                        ma  5 -{(a - u)(WI2 - 2~B’/~u(w’, + u(n2 - u2)1w’I2} - ;~dlw’1~.   (5.92)
                                                      W)
                        dt
                        ~
                   Provided that u < n and v  < a this may be made negative definite if  u is chosen positive
                   and sufficiently small. For example, letting u = a/k/3u2, equation (5.92) is re-written as

                                        {(kBu2 - l)lWI2 - 2B’/2u(w’, W) + (n2 - ~~)1w’1~).  (5.93)


                   BY  utilizing the expansion of I(B’/~uw/&TP - w’&?TP)~~ a similar way as in
                                                                           in
                   the foregoing, inequality (5.93) may be re-written as




                   The bracketed quantity is clearly positive definite if  (kBu2 - l)(n2 - u2) 2 Bu2; hence, if
                   k  is large enough (i.e. u small enough), we have the required behaviour: dHa/dt < 0 for
                   all w’  or W # 0, i.e. dHa/dt is globally negative definite. Hence, the trivial equilibrium
                   point wo = 0 is globally asymptotically stable if  u < n. It is of interest that if  a = 0, u
                                                                                 0;
                   must be  set to zero  also, and then  it can only be proved that dHa/dt I hence only
                   stability, but not asymptotic stability may be proved.
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