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16                SLENDER STRUCTURES AND AXIAL FLOW

                  2.1.4  Galerkin's method for a nonconservative system

                  Consider next that a fluid of constant velocity  U  and mass per unit length M  is flowing
                  through the pipe in the example of  Section 2.1.3, i.e. the pipe with the extra mass Me at
                  the free end. As shown in Chapter 3, the equation of motion in this case is

                                  a4,v       a2w        a2w           a2w
                                                            +
                               EI-    +MU2 - +2MU - (m +M) - 0,                       (2.40)
                                                                          =
                                   ax4       ax2        axat          at2
                  with boundary conditions (2.23) or (2.29) for Me = 0 and Me # 0, respectively.
                    For Me # 0, the problem is  solved by  the same two methods as before:  (a) with Me
                  included in the equation of  motion, with a Dirac delta function, and boundary conditions
                  (2.23);  (b) with  equation (2.40) as  it  stands and  boundary conditions (2.29). Table 2.2
                  gives  the  results  for  r = M,/[(rn + M)L] = 0.3  and  B  M/(m + M) = 0.1  for  two
                  values  of  the dimensionless flow  velocity  u = (M/IYI)'/~LU. Two  interesting observa-
                  tions may  be made from the results of Table 2.2. First, for u = 2, the eigenfrequencies
                  are no longer real; in fact, for all u # 0 they need not be real because the system is noncon-
                  servative.  Second, the eigenfrequencies for  u = 2 (again, for all  u # 0) as obtained by
                  the two methods are not identical as they should have been.
                    That the system is nonconservative may  be  assessed by  calculating the rate of  work
                  done by  all the forces acting on the pipe. If  it is zero, then  there is  no  net energy flow
                  in and out of the system, which must therefore be conservative; otherwise, the system is
                  nonconservative. In this case,

                                            dW
                                             dt                                        (2.41)
                  is found not to be zero by virtue of the forces represented by the second and third terms in
                  (2.40)+ - see Chapter 3. Viewed another way, this means that it is not possible to derive
                  these forces from a potential; like dissipative forces, for instance, they are nonconservative,
                  at least for this set of boundary conditions.
                    The second observation suggests that, for u # 0, the results from either method (a) or
                  (b) must be wrong. Indeed, those of method (b), utilizing equations (2.40) and (2.29) as
                  they stand, are wrong because of  the remark made at the end of Section 2.1.3. There is


                  Table 2.2  The  lowest  two  eigenfrequencies calculated  by  two  different  methods  for  different
                  u; r = 0.3, /3  = 0.1. In method (a) the extra mass, Me, is included in the equation of motion via a
                         Dirac delta function, while in (b) it is accounted for in the boundary conditions.
                                                 u=o                         I1 = 2
                                        Method (a)   Method (b)    Method (a)     Method  (b)
                  R1 [EI/(m + M) L4]-'l2   2.36         2.36       2.7  1 + 0.660i   2.18+  1.16i
                  Rz [EI/(m + M)L4]-1/2    17.58       17.58      16.48 + 0.084i   16.34 + 1.56i


                    +In this  problem,  the  definition of  Y is  not  clear-cut,  because  of  the  mixed  derivative.  However,  by
                  taking  ~[wI = [E1(#/ax4) + MU2(a2/ax2) + 2MU(a2/ax ar)]w, one  obtains  (dW/dt)  = -MU[(aw/at)2 +
                  u(aw/ax)(wat)l/ X=L  # 0.
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