Page 132 - Foundations Of Differential Calculus
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6. On the Differentiation of Transcendental Functions  115
         VI. If y = e arcsin x , this formula can also be differentiated by the preceding
             methods. Indeed, we have

                                               dx
                                       arcsin x
                                 dy = e     √       .
                                              1 − x 2


        In this way all functions of x involving not only logarithms and exponen-
        tials, but also even circular arcs, can be differentiated.

        200. Since the differentials of arcs when divided by dx are algebraic quan-
        tities, their second, and higher, differentials can be found, as we have
        shown, by differentiation of algebraic quantities. Let y = arcsin x. Since
                √
                      2
        dy = dx/ 1 − x ,wehave
                                  dy      1
                                     = √       ,
                                  dx     1 − x 2
                                          2
                                               2
        whose differential gives the value of d y/dx , provided that we keep dx
        constant. Hence the differentials of this y of any order are of this kind.
          If y = arcsin x, then

                                  dy      1
                                     = √       ,
                                  dx     1 − x 2

        and when we keep dx constant,

                             2
                            d y  =    x     ,
                            dx 2  (1 − x ) 3/2
                                       2
                             3
                            d y  =  1+2x 2  ,
                                       2
                            dx 3  (1 − x ) 5/2
                             4           3
                            d y  =  9x +6x  ,
                            dx 4  (1 − x ) 7/2
                                       2
                                        2
                             5
                            d y  =  9+72x +24x 4  ,
                                         2
                            dx 5    (1 + x ) 9/2
                             6              3       5
                            d y  =  225x + 600x + 120x  ,
                            dx 6      (1 − x ) 11/2
                                           2
                               ....
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