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Review of Probability and Random Variables  3.31

                      (b) What is P (C)?
                       (c) What is the P (A and C) = P (A∩ C)?
                      (d) Compute P (A|C).
                      Problem 3.23. This problem examines the sum of two random variables and works
                      through the computation of the resulting PDF. Formally Y = X 1 + X 2 .
                      (a) Use rand in Matlab and produce two vectors, X 1 and X 2 of 1000 indepen-


                          dent samples of a uniform random variable. The rand function produce
                          random variable uniformly distributed on [0, 1]. Add these two vectors to-
                          gether and plot a histogram of the resulting vector.
                      (b) Find the CDF of Y in the form


                                        F Y (y) =     ···     p X 1 ,X 2  (x 1 , x 2 )dx 1 dx 2  (3.37)
                                                 i    R i (y)
                          as given in Section 3.3.4. Identify all regions in the x 1 x 2 plane, R i (y), where
                          x 1 + x 2 < y where y is a constant.
                       (c) Find the PDF by taking the derivative of the CDF in (b) and simplify as
                          much as possible.
                      (d) Show that if X 1 and X 2 are independent random variables then the resul-
                          tant PDF of Y is given as the convolution of the PDF of X 1 and the PDF X 2 .
                      (e) Compute the PDF of Y if X 1 and X 2 are independent random variable
                          uniformly distributed on [0, 1]. Looking back at the histogram produced
                          in (a), does the resulting answer make sense? Verify the result further by
                          considering 10,000 length vectors and repeating (a).

                      Problem 3.24. A commonly used expected value in communication system analysis
                      is the characteristic function given as
                                                             ∞

                                     φ X (t) = E[exp( jXt)] =  exp( jxt) p X (x)dx       (3.38)
                                                            −∞


                      (a) Show that

                                                             dφ X (t)
                                                  E[X] =− j                              (3.39)
                                                               dt
                                                                    t=0
                      (b) Show that
                                                               n
                                                    n
                                               E[X ] = (− j ) n  d φ X (t)               (3.40)
                                                                  n
                                                                dt
                                                                      t=0
                          The results in parts (a) and (b) are known as the moment generating prop-
                          erty of the characteristic function.
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