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26 Fundamentals of Probability and Statistics for Engineers
0.4 0.95
A 0.05 B
0.1
0.6 0.9
A B
Figure 2.7 Probabilities associated with a binary channel, for Example 2.12
that
P
B P
BjAP
A P
BjAP
A 0:95
0:4 0:1
0:6 0:44:
The probability of interest in part (b) is P AjB), and this can be found using
Bayes’ theorem [Equation (2.28)]. It is given by:
P
BjAP
A 0:95
0:4
P
AjB 0:863:
P
B 0:44
It is worth mentioning that P(B) in this calculation is found by means of the
total probability theorem. Hence, Equation (2.29) is the one actually used here
in finding P AjB). In fact, probability P(A) in Equation (2.28) is often more
conveniently found by using the total probability theorem.
Example 2.13. Problem: from Example 2.11, determine P B 2 jA 2 ), the probabil-
ity that a noncritical level of peak flow rate will be caused by a medium-level storm.
Answer: from Equations (2.28) and (2.29) we have
P
A 2 jB 2 P
B 2
P
B 2 jA 2
P
A 2
P
A 2 jB 2 P
B 2
P
A 2 jB 1 P
B 1 P
A 2 jB 2 P
B 2 P
A 2 jB 3 P
B 3
0:8
0:3
0:293:
1:0
0:5 0:8
0:3 0:4
0:2
In closing, let us introduce the use of tree diagrams for dealing with more
complicated experiments with ‘limited memory’. Consider again Example 2.12
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