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REAL GAS FLOW: GAS WELL TESTING                              288


                                                                              k = iteration
                                                                                   counter
                                                           k = 1


                                                            k
                                                         µ
                                                               µ
                                                        (c)   = (c)  i
                                                          (c) A
                                                                    )
                                                    t k sss  =  φµ  k  (t DA SSS
                                                         .000264k
                             k

                         (c)  = (c) k-1
                          µ
                                µ
                                                (RE)-PLOT HORNER BUILDUP
                                                                t k  +∆ t
                                                    m(p ws  ) vs. log  SSS
                                                                    t ∆
                           k = k +  1

                                                  EXTRAPOLATES TO m(p*) k
                                                                     * k
                                                                TO m(p )
                                                   k     p  k                       )
                                                                              A
                                                                                DA
                                        MBH      m(p*)        m( )   =  constant  =   m log (C  (t ) SSS
                                                          k
                                                                  k
                                                         p
                                                       m( )              p
                                         k
                                      (c)  = (c)      k = 1  k  k > 1
                                            µ
                                      µ
                                                k
                                                p
                                                             MATERIAL BALANCE
                                                                k
                                                                p     p i   k
                                                            d       =−  Q t
                                                                          1SSS
                                                                Z    Z G
                                                                      i
                                                                d(p )
                                                                   k
                                                                 k     k    k
                                                                p SSS  −  p +  d(p )
                                                                 (c)    (c)  k
                                                                     k
                                                                       µ
                                                                  µ
                                                                         p SSS

                                                               k = 2  k  k > 2


                                                             +        k     k-1          -
                                                                    p  SSS  −  p  SSS  −  TOL
                                                                                            p  k  +  p  k-1
                                                                                         p =
                                                                                                2

                                                                                           10
                     Fig. 8.17  Iterative determination of  p in a gas well test analysis (Kazemi )
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