Page 41 - Fundamentals of Reservoir Engineering
P. 41

CONTENTS                                        XLI


                                             Cumulative Production
                t  =  Effective flowing time  =                                          (7.14)     156
                                                  Final flow rate

                                                        r
               dimensionless radius                        r D =                         (7.15)     161
                                                       r
                                                        w
                                                          kt
               dimensionless time                           t D =                        (7.16)     161
                                                       φµ  cr  w 2

                                                        2kh
                                                          π
               and dimensionless pressure   p(r ,t ) =         (p − p )                  (7.17)     161
                                                                     r,t
                                                   D
                                              D
                                                D
                                                                 i
                                                          qµ
                1 ∂      r  ∂ p    ∂ p D                                                 (7.18)     161
                             D

                r D  r ∂  D      D  r ∂  D    =  t ∂  D
                2kh
                 π
                      (p −  p ) =  p (t ) +  S                                           (7.19)     161
                       i
                           wf
                                     D
                                  D
                 qµ
                                    kt
                t D  =  0.000264       2  t in hours                                     (7.20)     162
                                           −
                                 φµ  cr  w
                                  kt
                t D  =  0.00634       2   t in days                                      (7.21)     162
                                           −
                                φµ cr  w
                                   kh
               p D  =  7.08 × 10 − 3     (p − p )                                        (7.22)     163
                                           i
                                              wf
                                  qB  o
                                   µ
                             4t
                   t
               p D  () =  1 2 ln  D                                                      (7.23)     164
                    D
                              γ
                   t
               p D  () =  1 2  (ln t +  0.809)                                           (7.24)     164
                    D
                               D
                                4A            r  2
               p(t ) =   1 2  ln    2  +  2 t π  D  w                                    (7.25)     164
                 D
                   D
                              γ Cr  w         A
                                 A
                         r  2    kt
                t  =  t   w  =                                                           (7.26)     165
                DA
                       D
                         A     φµ  cA
                                4A
               p(t ) =   1  ln        +  2 t                                             (7.27)     165
                                          π
                 D  D     2         2       DA
                              γ Cr  w
                                 A
                    r  2   4t r / A
                                  2
                            π
                Ct   w  ≈  e   D  w                                                      (7.28)     165
                 AD
                     A
                         4t
                          π
                Ct    ≈  e  DA                                                           (7.29)     165
                 ADA
                        kt
                t  =         ≈  0.1                                                      (7.30)     165
                DA
                      φµ cA
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