Page 44 - Fundamentals of Reservoir Engineering

CONTENTS XLIV

t +∆ t
log d = log (19.1 t DA ) (7.64) 199
t ∆
d
(p − p ) k
S = 1.151 ws(LIN) 1 -hr wf − log + 3.23
m φµ cr 2
w (7.52) 202
−
= 1.151 ( (4752 4506 ) − log 50 + 3.23
6
−
24.5 .2 1 20 10 × .09
×
××
t +∆ t
0.0144 ( 4800 p− ws(LIN) ) = 1.151 log + 25.63 (7.65) 206
t ∆
t +∆ t
0.0144 (4800 p− ws(LIN) ) = 1.151 log + 2 t DA − ½ ln (C t )
π
A DA
t ∆ (7.66) 207
t +∆ t
= 1.151 log + α
t ∆
0.0144 (p − p ws ) = p D ( D t D ) − p D ( t∆ D ) (7.67) 207
t + ∆
i
t +∆ t
0.0288 ∆ p ws = p DMBH ) (∆ t DA ) − ln (7.68) 208
(
t ∆
kh ( i p wf ) n ∆ q j
p −
t
7.08 10 − 3 n = p D ( D − t ) + S (7.69) 209
×
µ B o q n j1 q n n D − j 1
=
p −
3 kh ( i p wf 3 ) ( 1 ) 0 (q − q )
q −
t
t
7.08 10 − = p D ( ) + 2 1 p D ( D − t D )
×
D
µ B o q 3 q 3 3 q3 3 1 (7.70) 210
(q + q 2 )
3
t
+ p ( D − t ) + S
q 3 D 3 D 2
p − p ) n q
( i wf n versus ∆ j p t − t ) (7.71) 210
q n j1 q n D ( D n D −
j 1
=
p −
kh ( i p wf ) n ∆ q j k
7.08 10 − 3 n = 1.151 log t − t j 1 ) log 2 − 3.23 0.87S (7.72) 211
×
+
+
( n
−
µ B o q n j1 q n φµ cr w
=
p D ( ) α − 1 2 p D(MDH) (t ) (7.73) 212
′
t′ =
D
DA
kh N
7.08 10 − 3 ( i p wf ) = ∆ q p D ( D + t δ D − t D ) + q S
t
p −
×
N
j
−
µ B o n j1 N n j 1 (7.74) 217
=
n
(
+
+ ∆ qp δ t D − t δ ) (q − q N )S
j
D
n
jN 1 n D − j 1
=+
N N
t
t
∆ qp D ( D − t δ D − t D ) ∆ q p D ( D − t D ) (7.75) 217
≈
j
j
−
−
j1 N n j 1 j1 N j 1
=
=