Page 47 - Fundamentals of Reservoir Engineering
P. 47

CONTENTS                                      XLVII


                                1422 TQ        r   3
                  () m
               mp −      (p wf  ) =          ln  e  −  +  S    + FQ 2                    (8.25)     255
                                    kh         r w  4

                                1422 TQ        r    3
                              =              ln  e  −  +  S +  DQ                        (8.26)     255
                                    kh         r w  4

                     Fkh
               D =                                                                       (8.27)     255
                    1422T

                    constant
                β =                                                                      (8.28)     256
                       k α

                    constant
                β =       α                                                              (8.29)     256
                     (kk rg )

                                711QT      4t
                  () mp
               mp −      (   ) =          ln  D  +  2S′                                  (8.30)     257
                   i
                           wf
                                  kh        γ
                  kh
                           () mp
                                              t
                                                 +
                        (mp −     (   )) = m  () S′                                      (8.31)     257
                1422QT       i      wf      D  D
                              4t
               m D  () =  1 2  ln  D                                                     (8.32)     258
                    t
                    D
                               γ
                                4A
                    t
               m D  () =  1 2  ln    +  2 π  t DA                                        (8.33)     258
                    D
                              γ Cr 2
                                 Aw
                1 ∂     r  ∂ m    =  ∂ m D                                               (8.34)     258
                             D

                r ∂ r D    D  r ∂ D      t ∂  D
                D
                                        4t
                                                        t
                    t
               m D  () =  2π  t DA  +  1 2  ln  D  −  1 2  m DMBH  ( DA  )               (8.35)     258
                    D
                                         γ         (  )
                                kt (hrs )
                t DA  =  0.000264                                                        (8.36)     258
                                φµ cA
                                kh        *
                                        ( )
                       t
               m DMBH )  ( DA  ) =  711QT     mp  − mp                                   (8.37)     259
                                                ()
                  (
                  kh    (             ) )  m D t        1  ln  4A      S′                (8.38)     259
                           () mp
                                                  +
                                               D
                1422QT   mp −     (  wf  =    () S′ =    2    γ Cr 2  +
                                                                Aw
                  kh   ( mp      m           n   Q m     t     t  )    Q S′              (8.39)     260
                                          =
                            i
                1422T     () −     (p wf n  ) )    ∆  j  D  ( D n  −  D j 1  +  n  n
                                                                 −
                                             j1
                                             =
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