Page 48 - Fundamentals of Reservoir Engineering
P. 48
CONTENTS XLVIII
t
m D ( D n − t D j 1 ) = m D () = 2 t π ′ DA + 1 2 ln 4t′ D − 1 2 m DMBH ) ( DA )
t′
t′
D
(
γ
−
∆ Q = Q − Q j 1 (8.40) 260
j
j
−
and
S′ = S DQ n
+
n
kh ( ( 2 n Q m t t ) Q S (8.41) 260
() m p
−
=
i
1422T mp − wf n ) FQ n ) ∆ j D ( D n − D j 1 + n
−
j1
=
2
Q = C p − p 2 wf ) n (8.42) 262
( i
1422QT 4A
() mp
mp − ( wf ) = kh 1 2 ln γ C r 2 + S + FQ 2 (8.43) 263
i
Aw
mp i (p wf ) BQ FQ= + 2 (8.44) 263
() m−
mp i ( wf n )
() m p−
Q n versus Q n (8.45) 263
m(p ) m(p wf n ) FQ 2 n 2.359T n Q j 1422T 1 ln 4A S (8.46) 264
−
−
i
j
j1 Q
( ) c Ah
Q n = φµ i n t ∆ + kh 2 γ C r 2 +
=
A w
m(p ) m(p wf n ) FQ 2 n n Q j
−
−
i
Q n versus n t ∆ j (8.47) 264
j1 Q
=
2
6
m(p) = (0.3457p — 414.76) × 10 psia /cp (8.48) 265
() ( )
mp − mp wf n − FQ 2 n n ∆ Q j k
i
+
( n
j1 Q
( ) c r
Q n = m n log t − t j 1 ) m log+ φµ i w 2 − 3.23 .87S (8.49) 273
−
=
m(p ) m(p wf n ) FQ 2 n 1422T n ∆ Q j 1422T
−
−
i
t
j1 Q
Q n = kh n m D ( D n − t D − j 1 ) + kh S (8.50) 275
=
m(t ) ′ = α − 1 2 m D(MBH) (t ) (8.51) 275
′
D
D
DA
kh t ) m ( t ) (8.52) 279
=
−
D
ws
i
D
1422Q T (m(p ) m(p )) m (t + ∆ D − D ∆ D
1
1
kh (m(p ) m(p )) 1.151 log t +∆ t 1 ln 4t D 1 (8.53) 279
1
D
D
1422Q T i − ws(LIN) = t ∆ + m (t ) − 2 γ
1
1
1637Q T
m = 1 (8.54) 280
kh
(m(p ws(LIN)1 hr ) m(p )) k
−
wf
S′ = S DQ = 1.151 − − log 2 + 3.23 (8.55) 280
+
1
1
( c)r
m φµ iw