Page 49 - Fundamentals of Reservoir Engineering
P. 49

CONTENTS                                      XLIX


                               1637Q T                k
                                                                  +
                     −
               m(p ) m(p ) =         1    log t log        −  3.23 0.87S′ 1              (8.56)     280
                                              +
                   i
                          wf
                                                    ( c) r
                                  kh               φµ   iw 2
                                     (m(p ) m(p )    )        k
                                          −
                                                  −
                      +
                S′ =  S DQ = 1.151       i      wf 1 hr  − log    2  + 3.23              (8.57)     280
                 1
                           1
                                                            ( c)r
                                            m              φµ   iw
                  kh
                                                            ′
                                                                           ′
                                                                   ∆
                                     =
                            −
                      (m(p ) m(p )) Q (m (t + ∆      t D  + t ) m ( t D  +  t ))
                                                              −
                                  wf
                                                D
                                                                 D
                                                           D
                                             D
                                                                           D
                           i
                                         1
                1422T                           1     max             max                (8.58)     281
                                     +  Qm (t ) Q S′    2
                                                ′ +
                                                D
                                             D
                                                     2
                                         2
                  kh                     kh   (m(p ) m(p )) Q m (t ) Q S′                (8.59)     281
                                                         ′
                            −
                                  wf
                           i
                1422T  (m(p ) m(p )) = 1422T      i  −   ws  +  2   D  D ′ +  2  2
                                       (m(p )    − m(p )            k
                                           ′
                                              −
                                                         −
                        +
                 S′ =  S DQ =   1.151      ws 1 hr    wf 1 hr  − log   2  +  3.23        (8.60)     281
                   2
                             2
                                                                  ( c) r
                                                m                φµ   iw
                       (c)
                     φµ    p  A
                t   =       SSS  (t )                                                    (8.61)     286
                SSS
                     0.000264k    DA SSS
                       p  k(S )
               m(p) =     ro  o  dp                                                      (8.62)     289
                 ′
                       p b  µ o  B o
                                                                             k rg µ  B
               or                                                    RR +          o   o   (8.63)   289
                                                                       =
                                                                          s
                                                                             µ g  k ro  B g
                                        4t
                 ′
               m(t ) =  2 π  t DA  +  1 2  ln  D  −  1 2  m′ D(MBH) (t )                 (8.64)     290
                 D
                                                        DA
                    D
                                         γ
                    S     ∂ R   ∂ B    S ∂  B g
                                         g
                c =  o    B g  s  −  o     −   + c S wc  + c f                           (8.65)     290
                 t
                                                 w
                    B o    ∂ p   ∂ p     B ∂ p
                                         g
                1 ∂    ∂ β    φµ c ∂ β
                             =                                                           (8.66)     291
                r ∂ r    r ∂    k   t ∂
                1 ∂    r  ∂ β    =  ∂ β D                                                (8.67)     292
                           D


                r ∂ r D    D  r ∂ D    t ∂  D
                D
                  α
                      f(p) =  β D (t ) S                                                 (8.68)     292
                                +
                             D
                   q
                        n
                    n
               α f(p) =   ∆ q β D (t D n  − t D j 1 ) q S                                (8.69)     292
                                          +
                             j
                                            n
                        j1             −
                        =
                                                  4t′
                                                                 ′
                β o (t D  − t D  ) =  β D (t ) ′ =  2π  t′ +  1 2 ln  D  −  1 2  β D(MBH) (t )  (8.70)  292
                                                                 DA
                                          DA
                                 D
                         j 1
                    n
                         −
                                                   γ
                                          4t′
                β D (t D  − t D  ) =  β D  (t ) ′ =  1 2 ln  D                           (8.71)     293
                                  D
                    n
                         j 1
                         −
                                           γ
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