Page 50 - Fundamentals of Reservoir Engineering
P. 50

CONTENTS                                          L


                   r
               r =                                                                        (9.1)     298
                D
                   r
                    o
                      kt
                t =     2                                                                 (9.2)     298
                D
                    φµ cr 0

                          qµ
                qt                                                                        (9.3)     299
                  () =
                    D
                 D
                        2kh p
                            ∆
                         π
                                 2
                W e     =  2πφ hcr ∆ pW t D                                               (9.4)     299
                                        ()
                                      D
                                 0
                W e     =  U p W (t )                                                     (9.5)     299
                            ∆
                                 D
                                    D
               U        =  2 f hcr o 2                                                    (9.6)     299
                           πφ
                                kt
                t = constant×     2                                                       (9.7)     300
                D
                              φµ cr 0
                               2
               U = 1.119 fφhcr  (bbl/psi)                                                 (9.8)     300
                               o
                                kt
               t D = constant ×   2                                                       (9.9)     301
                              φµ cL
               U = .1781 wLhφc  (bbl/psi)                                                (9.10)     301
                                     2
               Radial W D  (max =  1 2  ( eD  −  ) 1                                     (9.11)     301
                               )
                                    r
               Linear W D  (max ) 1=                                                     (9.12)     301


                          φ kct
                W =  2hw       ×∆ p (ccs)                                                (9.13)     301
                  e
                           πµ


                              3
                             −
                                          ∆
                W =  3.26 10 hw    φ kct  x p       (bbls)                               (9.14)     302
                         ×
                  e
                                    πµ
                    p + p 1
                      i
                 p =
                  1
                       2
                     p + p
                 p =  1   2
                  2
                       2
                                                                                         (9.15)     309



                    p   + p
                      −
                 p =  j 1  j
                  j
                       2
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