Page 55 - Fundamentals of Reservoir Engineering
P. 55

CONTENTS                                        LV



               N pd bt  =  W id bt  =  q t = ( S w − S wc )  =  df 1                    (10.28)     356
                             id bt
                                      bt
                                                dS w
                                                   w S
                                                      w bt
                    W
                t =  q id bt                                                            (10.29)     356
                bt
                      id
                                   1
                S w = S  + (1 f )                                                       (10.30)     356
                            −
                      we
                              we
                                  df w
                                  dS
                                    w S
                                       we
                S w = S we  + (1 f )W id                                                (10.31)     356
                            −
                              we
               N pd = S w − S wc = (S we − S wc) + (1 − f we) W id(PV)                  (10.32)     356
                           1
                f ws  =                                                                 (10.33)     359

                    1+  B w       1  − 1
                        B o   f w

                     k(S )/ µ +   k (S )/ µ
               M =    ro  wf   o   rw  wf   w                                           (10.34)     360
                 s
                               ′
                              k/ µ
                               ro  o
                t =  4.39 W id  (years)                                                 (10.35)     362
                      µ     µ         ∂            ∆ ρ  gsinθ
               u t    o  −    w     = −  (p − p )+           6                          (10.36)     366
                                              w
                                          o
                      kk′ ro  kk′ rw    x ∂       1.0133 10
                                                          ×
                           dy   1
               M1      G           + 1                                                  (10.37)     367
                  −=
                            dx tanθ
                    kk′  A ∆  ρ  g sinθ
                G =   rw                                                                (10.38)     367
                     1.0133 10  6  q µ w
                            ×
                                   t
                              kk′   A ∆ γ  sinθ
                G =  4.9 10 − 4  rw                                                     (10.39)     367
                       ×
                                     q µ w
                                      t
                dy             M 1 G                                                    (10.40)     367
                                 −−
                dx  =−  tan β =       G       tanθ

                       kk′  A ∆ ρ  g sinθ
                q crit  =  rw   6                   r.cc / sec                          (10.41)     368
                                        −
                     1.0133 10 µ    w (M 1)
                             ×
                      4.9 10 − 4  kk′  A ∆ γ  sinθ
                         ×
                q crit  =         rw                rb / d                              (10.42)     368
                                    −
                               µ w (M 1)
                     S w − S
               b =         wc                                                           (10.43)     369
                   1S −     S wc
                     −
                        or
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