Page 42 - Fundamentals of Reservoir Engineering

CONTENTS XLII

2 π kh n
t
( p − p wf ) = ∆ q p D ( D − t D ) + q S (7.31) 170
i
n
j
µ n j1 n j1
−
=
2kh
π
−
∆
(p p ) = p (t + ∆ t ) p ( t ) (7.32) 171
−
D
i
D
ws
D
D
D
qµ
p-p
2kh ( i wf n ) = ∆ q j p t − t ) + S (7.33) 172
n
π
µ q n j = 1 q n D ( D n D − j 1
r
2t 3 ∞ e − α n 2t D J 2 1 (α n eD )
t
p D () = D + lnr eD − + 2 (7.34) 173
D
2
( ))
r eD 4 n1 α 2 n ( 1 2 (α n eD ) J α n
2
r
J
−
=
1
2kh t +∆ t 4t +∆ t D )
π
( D
(p − p ) = 1 2 ln + p (t + ∆ t ) − 1 2 ln (7.35) 174
i
ws
D
D
D
qµ t ∆ γ
2kh t +∆ t 4t
π
(p − p ) = 1 2 ln + p (t ) − 1 2 ln D (7.36) 174
i
ws
D
D
qµ t ∆ γ
2kh t +∆ t 4t D
π
t
(p − p ws(LIN) ) = ½ ln + p D () − ½ln (7.37) 174
i
D
qµ t ∆ γ
2kh 2 khqt
π
π
( p − ) p = = 2π t DA (7.38) 175
i
µ
qµ q cAhφ
2kh ( p − p * ) = p (t ) − 1 ln 4t D (7.39) 176
π
qµ i D D 2 γ
4kh ( p − p = 4 π t + ln 4t D − 2p () (7.40) 176
*
π
)
t
qµ DA γ D D
2kh 4t D ∞ φµ ca 2 j
π
t
(p − p wf ) = p D ( ) = 1 2 ln + 1 2 ei (7.41) 177
i
D
qµ γ j2 4kt
=
4t
p D () = 2 t DA + 1 2 ln D − 1 2 p D(MBH) ( DA ) (7.42) 182
t
t
π
D
γ
4kh *
π
)
p D(MBH) ( DA ) = ( p − p = 4 t DA (7.43) 182
t
π
qµ
4kh * r 2
π
)
p D(MBH) ( DA ) = ( p − p = ln C t w = ln (C t ) (7.44) 182
t
A DA
A D
qµ A
4kh *
π
t
p D(MBH) ( DA = ) 1 = ( p − p ) = ln C A (7.45) 183
qµ t DA = 1
4A
p D ( DA ) = 2 t DA + 1 2 ln t DA + 1 2 ln 2 − 1 2 p D(MBH) ( DA ) (7.46) 183
t
t
π
r γ w
+
0.0189(3500 − p ) = 2 t DA + ½ In t DA + 8.632 − ½ p D(MBH) (t ) 4.5 (7.46) 185
π
DA
wf