Page 96 - Fundamentals of Reservoir Engineering
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SOME BASIC CONCEPTS IN RESERVOIR ENGINEERING                          35

                                            10
                                                         ×
                                                                 ×
                                                    ×
                                   1.776x10 ×   0.19 0.8 35.37 4290                    9
                                =                                        =  699.70 10     scf
                                                                                   ×
                                                0.887 660
                                                     ×
                     2)   The overall production schedule can be divided into three parts, the build-up,
                          plateau production and decline periods, as shown in fig. 1.13.
                         Rate            G                                  G             G p
                           Q               p 1                                p 2            3
                       (MMscf /d)
                                                 Q   = 100 (MMscf/d)
                                                   o


                                       50 (MMscf /d)
                                                                                            20 (MMscf /d)


                                     t  1                 t  2                      t  3

                     Fig. 1.13  Gas field development rate− −− −time schedule (Exercise 1.2)

                          It is first required, to determine G , that is, the cumulative production when the
                                                           2 P
                          reservoir pressure has fallen to 1200 psia and the plateau rate can no longer be
                          maintained. When p = 1200 psia, Z = 0.832 (fig. 1.8) and using the depletion
                          material balance, equ. (1.35),

                                               p                         1200
                                               Z
                                                                   9
                                G =   G(1−      p    1200 ) =  699.70 10 (1=  0.832 )
                                                               ×
                                  p
                                                                         4290
                                   2
                                              i                          0.887
                                              Z i
                                G =   491.04 10  9  scf
                                             ×
                                  P
                                   2
                          Since the cumulative production during the two years build-up period is
                                                             6
                                                                                   9
                                G  = Q avg  × 2 × 365 = 50 × 10 × 2 × 365 = 36.5 × 10  scf
                                   1 P
                          the gas production at the plateau rate of 100 MMscf/d is
                                                                                9
                                                                  9
                                G  − G  = (491.04 – 36.50) × 10  = 454.54 × 10  scf
                                        p1
                                  p
                                   2
                          and the time for which this rate can be maintained is
                                      G −  G       454.54 10  9
                                                           ×
                                       p
                                t =     2    1 p  =               =  12.45 yrs
                                 2
                                                          6
                                         Q o      100 10 ×   365
                                                      ×
                          Therefore the time for which the plateau rate can be sustained will fall short of the
                          requirement by some 2.5 years.
                     3)   During the exponential decline period the rate at any time after the start of the
                          decline can be calculated as
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