Page 95 - Fundamentals of The Finite Element Method for Heat and Fluid Flow
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                        THE FINITE ELEMENT METHOD
                                Table 3.5
                                                      Collocation
                                              FEM
                                                                               Variational
                                                                  Sub-domain
                        Location (ζ)  Exact  Comparison of solutions obtained from different methods  Least
                                             5 linear                          or Galerkin  squares
                                            elements
                        0.0          0.343    0.340      0.294       0.250       0.318      0.375
                        0.1          0.348     –         0.301       0.258       0.325      0.381
                        0.2          0.364    0.361      0.322       0.280       0.345      0.400
                        0.3          0.390     –         0.358       0.316       0.380      0.431
                        0.4          0.429    0.426      0.407       0.370       0.427      0.475
                        0.5          0.480     –         0.471       0.438       0.490      0.531
                        0.6          0.546    0.543      0.548       0.520       0.563      0.600
                        0.7          0.628     –         0.640       0.618       0.652      0.681
                        0.8          0.729    0.727      0.746       0.730       0.755      0.755
                        0.9          0.851     –         0.866       0.858       0.870      0.881
                        1.00         1.00     1.00       1.00        1.00        1.00       1.00

                           Note that the last equation arises because of the constant temperature boundary condition
                        at node 6. On solving the system of equations using Gaussian elimination, we finally obtain
                        all the θ values. Table 3.5 shows the comparison between the exact result and all the other
                        computations from each of the different methods.
                           It can be observed from Table 3.5 that the methods used in conjunction with the assumed
                        profile satisfying the boundary conditions for the entire domain are less accurate compared
                        to the finite element method solution even with only five linear elements. It can also be
                        observed that the nodal values in the finite element method solution are very close to those
                        of the exact solution.


                        3.4 Formulation for the Heat Conduction Equation

                        In many practical situations, finding the temperature in a solid body is of vital importance
                        in terms of the maximum allowable temperature, for example, as in semiconductor devices,
                        maximum allowable displacement, for example, as in steam and gas turbines, maximum
                        allowable thermal stress and the maximum number of repeated thermal cycles in fatigue-
                        dominated problems. In this section, we shall give the derivation of the finite element
                        equations, both by the variational method as well as the Galerkin method, for the three-
                        dimensional heat conduction equation of stationary systems under steady state conditions.
                           The governing differential equation, as given in Chapter 2, is

                                       ∂     ∂T     ∂     ∂T     ∂     ∂T
                                           k x    +     k y   +      k z   + G = 0         (3.241)
                                       ∂x    ∂x     ∂y    ∂y     ∂z    ∂z
                        with the following boundary conditions
                                                                   T = T b on surface S 1
                                            ∂T      ∂T       ∂T
                                          k x  ˜ l + k y  ˜ m + k z  ˜ n + q = 0 on surface S 2
                                             ∂x      ∂y      ∂z
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