Page 341 - Global Tectonics
P. 341

324   CHAPTER 10



                           1.0                           1. 0
                               (a)                            (b)
                                                 α  =45°                       α  =0°
                           0.8                   η  =100  0. 8                 η =100
                                      –4 –2 0  2  4                  –4 –2 0  2  4
                           0.6                           0. 6
                                       -1
                           0.4       -3                  0. 4       -2        2
                                                    1
                           0.2      -2      4            0. 2      -3     3
                                                  2                    -1
                                               3                                 1
                        Distance x 10   km  1.0  (c)     1. 0  (d)              α
                       4   0.0  0.0  0.2  0. 4  0.6  0. 8  1.0  0. 0  0. 0  0 .2  0. 4  0 .6  0. 8  1.0


                                                 α
                                                  =0°
                                                                                 =3
                           0.8
                                      –4 –2 0  2  4  η =3  0. 8      –4 –2 0  2  4  η  =45°
                           0.6                           0. 6
                                     -1
                          0.4                            0. 4      -2
                                      -2       2                 -1
                                                                             3
                           0.2        -4      4  3       0. 2
                                                                     -4
                                                  1                              1
                                    -3
                           0.0                           0. 0      -3        2
                             0.0  0.2  0.4  0.6  0.8  1.0   0.0  0.2  0.4  0.6  0.8  1.0
                                                Distance x 10  km
                                                          4

           Figure 10.25  Results from finite element modeling showing the instantaneous lateral displacement field during

           indentation for two different indentor rheologies and two indentor angles (a) (image provided by J. Robl and modified

           from Robl & Stüwe, 2005a, by permission of the American Geophysical Union. Copyright © 2005 American Geophysical
           Union). (a) and (b) show a viscosity contrast between indentor and foreland of h = 100; (c) and (d) show a contrast of h
           = 3. Indentor angles of a = 0° and a = 45° are represented. Grayscale bar shows horizontal velocity. Contour interval is
                −1
           1 mm a . Eastward moving area is largest for the oblique indentor shown in (a).

                A three-dimensional viscoelastic model         boundary conditions are assigned to simulate
                  developed by Liu & Yang (2003) illustrates   the lateral escape of the crust. On the west,
                  how various possible driving forces and a    the effects of a spring or roller simulate the
                  rheological structure involving both vertical   lateral resisting force of a rigid block in
                  and lateral variations infl uence deformation   Pamir. On the northern side of the model
                  patterns in Tibet and its surrounding regions.   boundary conditions approximate the
                  This model, like most others, involves a rigid   resistance to motion by the rigid Tarim
                  Indian plate that collides with a deformable   Basin. The top surface approximates the real
                  Eurasian continent at a constant velocity    topography and the bottom lies at 70 km
                  relative to Eurasia. The two plates are      depth. A vertical topographic load is included
                  coupled across a fault zone that simulates the   by calculating the weight of rock columns in
                  Main Boundary Thrust (Fig. 10.26a). On the   each surface grid of the fi nite element
                  eastern and southeastern sides of the model,   model. An isostatic restoring force is applied
   336   337   338   339   340   341   342   343   344   345   346