Page 256 - Handbook Of Integral Equations
P. 256
b y(t)
7. dt = f(x), 0 < k <1.
a |g(x) – g(t)| k
Let g ≠ 0. The transformation
x
1
z = g(x), τ = g(t), w(τ)= y(t)
g (t)
t
leads to an equation of the form 3.1.30:
w(τ)
B
|z – τ| k dτ = F(z), A = g(a), B = g(b),
A
where F = F(z) is the function which is obtained from z = g(x) and F = f(x) by eliminating x.
1 y(t)
8. dt = f(x), 0 < k <1.
0 |g(x) – h(t)| k
Let g(0) = 0, g(1) = 1, g >0; h(0)=0, h(1) = 1, and h >0.
t
x
The transformation
1
z = g(x), τ = h(t), w(τ)= y(t)
h (t)
t
leads to an equation of the form 3.1.29:
1
w(τ)
|z – τ| k dτ = F(z),
0
where F = F(z) is the function which is obtained from z = g(x) and F = f(x) by eliminating x.
b
9. y(t)ln |g(x) – g(t)| dt = f(x).
a
Let g ≠ 0. The transformation
x
1
z = g(x), τ = g(t), w(τ)= y(t)
g (t)
t
leads to Carleman’s equation 3.4.2:
B
ln |z – τ|w(τ) dτ = F(z), A = g(a), B = g(b),
A
where F = F(z) is the function which is obtained from z = g(x) and F = f(x) by eliminating x.
1
10. y(t)ln |g(x) – h(t)| dt = f(x).
0
Let g(0) = 0, g(1) = 1, g >0; h(0)=0, h(1) = 1, and h >0.
t
x
The transformation
1
z = g(x), τ = h(t), w(τ)= y(t)
h (t)
t
leads to an equation of the form 3.4.2:
1
ln |z – τ|w(τ) dτ = F(z),
0
where F = F(z) is the function which is obtained from z = g(x) and F = f(x) by eliminating x.
© 1998 by CRC Press LLC
© 1998 by CRC Press LLC
Page 235