Page 57 - Handbook of Civil Engineering Calculations, Second Edition
P. 57

1.40            STRUCTURAL STEEL ENGINEERING AND DESIGN

                                                                Calculation Procedure:

                                                                1. Determine the relationship
                                                                between the torque in the shaft
                                                                segments
                                                                Since segments AB and BC (Fig. 24)
                                                                are twisted through the same angle,
                                                                the torque applied at the junction of
                                                                these segments is distributed in pro-
                                                                portion to their relative rigidities. Us-
                           FIGURE 24. Compound shaft.           ing the subscripts  s and  b to denote
                                                                steel and bronze, respectively, we see
                                                                that  	   T s L s /(J s G s )    T b L b /(J b G b ),
                                                                where the symbols are as given in the
                                                                previous calculation procedure. Solv-
                                                                ing yields T s   (5/4.5)(34/44)(12/6)T b
                                                                  0.703 T b .
                            2. Establish the relationship between the shearing stresses
                            For steel,  s ss   16T s /( D ), where the symbols are as given earlier. Thus  s ss
                                                3
                                      3
                                                                                 3
                                                                               3
                                                                  3
                            l6(0.703T b )/( 3 ). Likewise, for bronze, s sb   16T b /( 4 ),   s ss   0.703(4 /3 )s sb   1.67s sb .
                            3. Compute the allowable torque
                            Ascertain which material limits the capacity of the member, and compute the allowable
                            torque by solving the shearing-stress equation for T.
                              If the bronze were stressed to 10,000 lb/sq.in. (69.0 MPa), inspection of the above re-
                            lations shows that the steel would be stressed to 16,700 lb/sq.in. (115.1 MPa), which ex-
                            ceeds the allowed 15,000 lb/sq.in. (103.4 MPa). Hence, the steel limits the capacity. Sub-
                            stituting the allowed shearing stress of 15,000 lb/sq.in. (103.4 MPa) gives  T s
                                   3
                            15,000 (3 )/[16(12)    6630 lb·ft (8984.0 N·m); also,  T b   6630/0.703    9430 lb·ft
                            (12,777.6 N·m). Then T   6630   9430   16,060 lb·ft (21,761.3 N·m).




                                           Stresses in Flexural Members

                            In the analysis of beam action, the general assumption is that the beam is in a horizontal
                            position and carries vertical loads lying in an axis of symmetry of the transverse section
                            of the beam.
                              The vertical shear V at a given section of the beam is the algebraic sum of all vertical
                            forces to the left of the section, with an upward force being considered positive.
                              The bending moment M at a given section of the beam is the algebraic sum of the
                            moments of all forces to the left of the section with respect to that section, a clockwise
                            moment being considered positive.
                              If the proportional limit of the beam material is not exceeded, the bending stress (also
                            called the flexural, or fiber, stress) at a section varies linearly across the depth of the sec-
                            tion, being zero at the neutral axis. A positive bending moment induces compressive
                            stresses in the fibers above the neutral axis and tensile stresses in the fibers below. Conse-
                            quently, the elastic curve of the beam is concave upward where the bending moment is
                            positive.
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