Page 389 - Handbook of Electrical Engineering
P. 389

EARTHING AND SCREENING     377

           Find I c in terms of I 3 . Assume V in = 0 in order to determine the amount of current induced from I 3 .
           Let this amount be called I co .

                                               −jωM 3c · I 3
                                   I co =                          amps                   (13.7)
                                        R in + R c + R o + R e + jωL c
           Let the voltage appearing across the load be V oo :-

                                             −jωM 3c − R o · I 3
                                   V oo =                          volts                  (13.8)
                                         R in + R c + R o + R e + jωL c

           Let the core loop resistance be called R cc :-

                                       R cc = R in + R c + R o + R e  ohms                (13.9)

                 Note that the components R 3 and L 3 of the source are not included in this result because the
           interference is a current source, which is known.


           Case B. Signal cable with a screen.
           Assume that the screen is earthed at both ends at the same points as the signal source and the output
           load. Hence the common earth resistance R e is shared by both the screen and the core circuits. Again
           assume that V in is zero for the same reason as above.

                 The summation of voltages and emfs in the core loop of the signal cable is:-

                           V in = (R in + R c + jωL c )I c + (R o + R e )I c
                                + jωM 3c I 3 − jωM sc I s = 0, which upon rearranging is,

                                − jωM 3c I 3 = (R cc + jωL c )I c − jωM sc I s
           This has the form:-
                                                                                         (13.10)
                                             y 1 = a 11 I c + a 12 I s
           Where

                                             y 1 =−jωM 3c I 3
                                            a 11 =+(R cc + jωL c )

                                            a 12 =−jωM sc
           The summation of voltages and emfs in the screen loop of the signal cable is:-


                                0 = (R s + jωL s )I s − jωM 3s I 3 − jωM sc I c + R e I s

           which upon rearranging is,

                                   −jωM 3s I 3 =+jωM sc I c − (R ss + jωL s )I s
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