Page 577 - Handbook of Electrical Engineering
P. 577

570    HANDBOOK OF ELECTRICAL ENGINEERING

                  The parallel impedance of the running motor is Z mn :-

                                          R ms = 3.8244 and X ms = j0.9875 pu


                  The series impedance of the running motor is Z msl :-

                                       Z msl = R msl + jX msl = 0.2390 + j0.9257 pu


                       Now add the feeder cable impedance in series to obtain the total series impedance between
                  the MCC and the motor. Call this total impedance Z mlc .

                                  Z mslc = R mslc + jX mslc = R mslc + R cm + j(X mslc + X cm )

                                       = 0.00844 + 0.2390 + j(0.003175 + 0.9257)
                                       = 0.2475 + j0.9289 pu

                  The total load on the MCC consists of the static load Z ol1 (series components) in parallel with
                  the cable and motor Z mnsc (series components). The total impedance Z ols is therefore:-

                                                    Z oll × Z mslc
                                 Z ols = R ols + jX ols =      = 0.3050 + j0.7874 pu
                                                    Z oll + Z mnsc
                  The impedance seen at the SWBD for the cable, motor and MCC load is Z cs :-


                                 Z cs = Z ols + Z c = 0.3050 + j0.7874 + 0.00635 + j0.05446
                                              = 0.3114 + j0.8418 pu

                  This impedance is in parallel with that of the local load Z og on the SWBD. The total equivalent
                  load on SWBD is Z ogs where:-

                                                     Z ogl × Z cs
                                 Z ogs = R ogs + jX ogs =      = 0.3631 + j0.6375 pu
                                                     Z ogl + Z cs

                  Hence the total impedance seen by the generator emf E o is Z gs :-

                                        Z ogs = R g + R ogs + j(X g + X ogs )
                                            = 0.02 + 0.3631 + j(0.25 + 0.6375)
                                            = 0.3831 + j0.8875 pu


                  The current in the generator I gs is:-

                                              1.0687 − j0.1068
                                        E o
                                  I gns =   =                 = 0.5395 − j0.9713 pu
                                        Z gs  0.5395 + j0.9713
   572   573   574   575   576   577   578   579   580   581   582