Page 427 - Handbook of Energy Engineering Calculations
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calculate the rate at which the steam is being generated in the tube bank.


               Calculation Procedure:


                                                                        2
               1. Find the temperature of steam at 1000 lf /in (6900 kPa)
                                                                    f
               From Table 2, Saturation: Pressures, of the Steam Tables mentioned under
               Related Calculations of this procedure, the saturation temperature of steam at
                            2
               1000 lb/in  (6900 kPa), t  = 544.6°F (558 K), a constant value as indicated in
                                             s
               Fig. 9.

























                          FIGURE 9 Temperature vs surface area of boiler tubes.




               2. Determine the logarithmic mean temperature difference in terms of the
                  flue-gas leaving temperature
               The logarithmic mean temperature difference,Δt  = (Δt  –Δt )/{2.3  ×  log                   10
                                                                                           2
                                                                                    1
                                                                           m
               [(t   –  t )  /(t   –  t )]},  whereΔt   =  flue-gas  entering  temperature  =  steam
                               2
                                                      1
                                     s
                         s
                  1
               temperature = (t  – t ) = (2000 – 544.6);Δt  = flue-gas leaving temperature –
                                                                   2
                                        s
                                   1
               steam temperature = (t  – t ) = (t  – 544.6); (Δt  –Δt ) = [(2000 – 544.6) – (t              2
                                                                        1
                                                       2
                                                                              2
                                           2
                                                s
               – 544.6)] = (2000 – t ); [(t  – t )/(t  –  t )]  =  [(2000  –  544.6)/(t   –  544.6)].
                                                                 s
                                                                                              2
                                                       s
                                                 1
                                          2
                                                           2
               Hence,Δt  = [(2000 – t )/{2.3 × log  [(1455.4)/(t  – 544.6)]}.
                                                                           2
                           m
                                           2
                                                          10
               3. Compute the flue-gas leaving temperature
               Heat transferred to the boiler water, Q = w  × c  × (t  – t ) = UA Δt , where
                                                                                                  m
                                                                                     2
                                                                   g
                                                                         p
                                                                                1
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