Page 143 - How To Solve Word Problems In Calculus
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The law of cosines is often needed when dealing with problems
                               involving triangles other than right triangles.





                                             2
                                                  2
                                        2
                                       c = a + b − 2abcos θ               a             c
                                                                      θ
                                                                                b
                               Observe that if θ = π/2, the law of cosines reduces to the theo-
                                                        2
                                                             2
                                                   2
                               rem of Pythagoras: c = a + b . Other trigonometric identities
                               will be discussed as needed in the examples that follow.
                               Related Rates
                               EXAMPLE 1
                               Two sides of a triangle are 5 and 10 inches, respectively. The
                               angle between them is increasing at the rate of 5 per minute.
                                                                               ◦
                               How fast is the third side of the triangle growing when the
                               angle is 60 ?
                                         ◦

                                   Solution




                                                5                  x


                                             θ
                                                             10

                               Let θ represent the angle between the sides of length 5 and 10
                               and let x represent the length of the third side of the triangle.
                               In any calculus problem involving derivatives, all angles and
                               rates must be expressed in radian measure.

                                      dθ     π                              dx            π
                               Given:     =    radians per minute     Find:    when θ =
                                      dt    36                              dt            3

                                           180 ◦  π     
                       π
                                        ◦                                    ◦
                                       5 =     =   radians                 60 =  radians
                                            36   36                             3
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