Page 148 - How To Solve Word Problems In Calculus
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1
                                When the runner has run        of the way around the track,
                                                            4
                                θ = π/2. Triangle ORT then becomes a right triangle.

                                             2
                                                     2
                                            x = 100 + 100   2         s = r θ
                                              = 20,000                s = 100 θ
                                                     √              ds        dθ
                                             x = 100 2                 = 100
                                                                     dt       dt

                                                                              dθ
                                                                    10 = 100
                                                                              dt
                                                                    dθ     1
                                                                       =
                                                                    dt    10
                                                       dx
                                We can now compute       :
                                                       dt
                                                  dx               dθ
                                                x    = 10,000 sin θ
                                                  dt               dt
                                                                   1


                                              √   dx                 π       1
                                          100 2      = 10,000 · sin      ·
                                                  dt                 2      10
                                              √   dx
                                          100 2      = 1000
                                                  dt
                                                  dx    1000      10     √
                                                     =     √ = √ = 5 2 m/sec
                                                  dt   100 2       2


                                Maximum-Minimum Problems
                                Many maximum-minimum problems are conveniently solved
                                by introducing trigonometric functions.

                                EXAMPLE 5
                                What is the largest possible area of a triangle, two of whose
                                sides are a and b?





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