Page 38 - How To Solve Word Problems In Calculus
P. 38

8. Let the radius and height of the cylinder be represented by r and h,
                                    respectively.


                                                                 r


                                                             h    10
                                                             2


                                                                     h











                                                          2
                                                   V = πr h     S = 2πrh + 2πr  2
                                    By the Pythagorean theorem,

                                                               2
                                                            h
                                                       2            2
                                                      r +       = 10
                                                            2
                                                             h 2
                                                          2
                                                         r +    = 100
                                                              4
                                                                        h 2
                                                               2
                                                              r = 100 −
                                                                         4
                                                                  400 − h 2
                                                               2
                                                              r =
                                                                      4
                                                                  √
                                                                    400 − h 2
                                                              r =
                                                                       2
                                    It follows by substitution that
                                                                  √
                                                  2                       2                 2
                                           400 − h                 400 − h           400 − h
                                   V = π            h     S = 2π             h + 2π
                                              4                       2                 4
                                          π          3                         π         2
                                                                           2
                                   V (h) =  (400h − h )   S(h) = πh 400 − h +    (400 − h )
                                           4                                    2
                                                                                          25
   33   34   35   36   37   38   39   40   41   42   43