Page 39 - How To Solve Word Problems In Calculus
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9. Let x represent the number of trees to be planted in excess of 500.
                                   Let N(x) represent the number of apples as a function of x. The
                                   total number of trees is then 500 + x and each tree will produce
                                   800 − 20x apples.
                                     Total number of apples
                                        = (number of apples produced by each tree)(number of trees)

                                                  N(x) = (800 − 20x)(500 + x)
                                                       = 400,000 − 9200x − 20x 2

                              10. Let x represent the number of computers sold. The cost of
                                   producing x computers is the sum of the fixed cost and the variable
                                   cost.

                                                      C = 2000 + 800x

                                                          Fixed cost  Cost to make
                                                                  x computers
                                   If 10 or fewer computers are sold, the price is $1500 per computer, so
                                   the company’s revenue R = 1500x. The profit,

                                                    P = R − C
                                                      = 1500x − (2000 + 800x)

                                                      = 700x − 2000
                                        If more than 10 computers are sold, the number of computers in
                                   excess of 10 is x − 10. The price per computer then becomes
                                   1500 − 10(x − 10) = 1600 − 10x dollars. In this case the
                                   company’s revenue becomes R = (1600 − 10x)x = 1600x − 10x 2
                                   and the profit
                                                P = R − C
                                                                2
                                                   = 1600x − 10x − (2000 + 800x)
                                                               2
                                                   = 800x − 10x − 2000
                                   Combining these results,
                                                     700x − 2000            if x ≤ 10

                                             P (x) =           2
                                                     800x − 10x − 2000      if x > 10



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