Page 297 - Improving Machinery Reliability
P. 297

268   Improving Machinery Reliability

                      One of many such examples would be Figure 5-2, which illustrates the reduction
                    in bearing failures actually experienced by a U.S. Gulf Coast petrochemical compa-
                    ny in the span of 4% years. Although these improvements are undoubtedly attribut-
                    able to a combination of procedural, organizational, and hardware-specific improve-
                    ment  measures, let us  suppose for the sake of reasonable illustration that  this
                    downturn in the number of bearing replacements was related to pumps. We will fur-
                    ther  assume that  incorporating  improved  components during repair  events  would
                    typically add  $500 to the average pump repair cost of  $6,700. However, the $500
                    add-on applies only if implemented when pumps are in the shop for repairs of  any
                    kind. It has been estimated that implementation on the basis of purposely taking a
                    pump to the shop to effect these improvements would cost $3,470 per pump.
                      At issue is whether “Unit C” at this facility should implement option  1; Le., to
                    have its 232 pumps retrofitted with the requisite component upgrades at $3,470 per
                    pump or option 2, “upgrading whenever in the shop for other reasons,” or whether
                    option 3, “leaving everything as is” (business as usual) is financially more attractive.
                    This is how we might proceed.
                      From Figure 5-2, note that the mean failure rate in February 1990 was 17.7 bear-
                    ing failures per  1,000 pieces of rotating equipment. By March  1994, this mean rate
                    of  failure had been reduced to 6.7.  Option  1, conversionlupgrading of  232 pumps
                    during the next  shutdown  would  cost $(232)  (3470) = $805,040.  This one-time
                    expenditure would likely result in yearly savings of  (17.7-6.7) (0.232) (12 months)
                    ($6,700) = $205,181. The resulting payback period would be 805,040/205,181 = 3.9
                    years and  savings over a 4%-year period  would  amount to ($205,181)  (4.5)  =
                    $923,3 15.
                      Next, we’ll examine option 2 with the assumption that we could expect to dupli-
                    cate the published experience of the U.S. Gulf Coast petrochemical company men-

                                - - - -



                       70
                    .-   60            C  UCL      C  LCL      C  MEAN     C  RATE
                       50
                    p  40
                    2  30
                    0  20
                    P
                    23  ’0
                    s
                     h  0

                      -30


                                                     Individuals
                         Figure 5-2. Bearing failure rate per 1,000 machines at a US. chemical plant.
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