Page 154 - Intro Predictive Maintenance
P. 154

Vibration Monitoring and Analysis  145


                                  M 2  ˙˙
                                                   (
                                     X 2 =- K X 2 +  K X 1 -  X 2 )
                                                  3
                                            2
                                   g c
            or
                                 M 2  ˙˙
                                               )
                                     X 2 + ( K 2 +  K X 2 -  K X 1 =  0
                                               3
                                                     3
                                  g c
            If we assume that the masses, M 1 and M 2, undergo harmonic motions with the same
            frequency, w, and with different amplitudes, A 1 and A 2, their behavior can be repre-
            sented as:
                                        X 1 =  A 1 sin w t
                                                 ()
                                                 ()
                                        X 2 =  A 2 sin w t
            By substituting these into the differential equations, two equations for the amplitude

                 A 1
            ratio,   ,  can be found:
                 A 2
                                               -
                                      A 1       K 3
                                        =
                                          M 1
                                     A 2      2
                                             w  -  K 1 -  K 3
                                          g c
            and

                                          M 2  2
                                             w  -  K 2 -  K 3
                                     A 1  g c
                                        =
                                               -
                                     A 2        K 3
            For a solution of the form we assumed to exist, these two equations must be equal:


                                                M 2  2
                                                  w  - K 2  - K 3
                                    -K 3        g c
                                             =
                                M 1  2              -K 3
                                  w  - K 1  - K 3
                                g c
            or

                              ÏK 1 + K 3  K 2 + K 3 ¸ KK 2 + K K 3 + KK  3
                                                               1
                                                         2
                                                   1
                             2
                         4
                       w -  w Ì       +       ˝ +      MM         =  0
                                          2
                              Ó Mg c    Mg c  ˛          1  2
                                  1
                                                          2
                                                        g c
                                                                      2
            This equation, known as the frequency equation, has two solutions for w . When sub-
            stituted in either of the preceding equations, each one of these gives a definite value
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