Page 251 - Intro to Tensor Calculus
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The generalized Hooke’s law can now be expressed in a form where the 36 independent constants can
be examined in more detail under special material symmetries. We will examine the form
e 1 s 11 s 12 s 13 s 14 s 15 s 16 σ 1
s 21 s 22 s 23 s 24 s 25
e 2 s 26 σ 2
s 31 s 32 s 33 s 34 s 35
. (2.4.6)
e 3 s 36 σ 3
=
s 41 s 42 s 43 s 44 s 45
e 4 s 46 σ 4
e 5 s 51 s 52 s 53 s 54 s 55 s 56 σ 5
e 6 s 61 s 62 s 63 s 64 s 65 s 66 σ 6
Alternatively, in the arguments that follow, one can examine the equivalent form
σ 1 c 11 c 12 c 13 c 14 c 15 c 16 e 1
c 21 c 22 c 23 c 24 c 25
σ 2 c 26 e 2
c 31 c 32 c 33 c 34 c 35
.
σ 3 c 36 e 3
=
c 41 c 42 c 43 c 44 c 45
σ 4 c 46 e 4
σ 5 c 51 c 52 c 53 c 54 c 55 c 56 e 5
σ 6 c 61 c 62 c 63 c 64 c 65 c 66 e 6
Material Symmetries
A material (crystal) with one plane of symmetry is called an aelotropic material. If we let the x 1 -
x 2 plane be a plane of symmetry then the equations (2.4.6) must remain invariant under the coordinate
transformation
x 1 10 0 x 1
x 2 = 01 0 x 2 (2.4.7)
x 3 00 −1 x 3
which represents an inversion of the x 3 axis. That is, if the x 1 -x 2 plane is a plane of symmetry we should be
able to replace x 3 by −x 3 and the equations (2.4.6) should remain unchanged. This is equivalent to saying
that a transformation of the type from equation (2.4.7) changes the Hooke’s law to the form e i = s ij σ j where
the s ij remain unaltered because it is the same material. Employing the transformation equations
x 1 = x 1 , x 2 = x 2 , x 3 = −x 3 (2.4.8)
we examine the stress and strain transformation equations
∂x p ∂x q ∂x p ∂x q
σ ij = σ pq and e ij = e pq . (2.4.9)
∂x i ∂x j ∂x i ∂x j
If we expand both of the equations (2.4.9) and substitute in the nonzero derivatives
∂x 1 ∂x 2 ∂x 3
=1, =1, = −1, (2.4.10)
∂x 1 ∂x 2 ∂x 3
we obtain the relations
σ 11 = σ 11 e 11 = e 11
σ 22 = σ 22 e 22 = e 22
σ 33 = σ 33 e 33 = e 33
(2.4.11)
σ 21 = σ 21 e 21 = e 21
σ 31 = −σ 31 e 31 = −e 31
e 23 = −e 23 .
σ 23 = −σ 23