Page 368 - Intro to Tensor Calculus
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362



                                                   APPENDIX C
                                            VECTOR IDENTITIES


                   The following identities assume that A, B, C, D are differentiable vector functions of position while
                                                     ~ ~ ~ ~
               f, f 1 ,f 2 are differentiable scalar functions of position.




                               1.                        A · (B × C)= B · (C × A)= C · (A × B)
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                                2.                           A × (B × C)= B(A · C) − C(A · B)
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                                3.             (A × B) · (C × D)= (A · C)(B · D) − (A · D)(B · C)
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                                4.                 A × (B × C)+ B × (C × A)+ C × (A × B)= 0
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                                5.              (A × B) × (C × D)= B(A · C × D) − A(B · C × D)
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                                                                 = C(A · B × C) − D(A · B × C)
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                                                                                          ~ 2
                                6.                    (A × B) · (B × C) × (C × A)= (A · B × C)
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                                7.                                     ∇(f 1 + f 2 )= ∇f 1 + ∇f 2
                                8.                                  ∇· (A + B)= ∇· A + ∇· B
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                                9.                               ∇× (A + B)= ∇× A + ∇× B
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                               10.                                   ∇(fA)= (∇f) · A + f∇· A
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                               11.                                    ∇(f 1 f 2 )= f 1 ∇f 2 + f 2 ∇f 1
                               12.                             ∇× (fA)=)∇f) × A + f(∇× A)
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                               13.                       ∇· (A × B)= B · (∇× A) − A · (∇× B)
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                                                                          |A|
                               14.                          (A ·∇)A = ∇         − A × (∇× A)
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                               15.   ∇(A · B)= (B ·∇)A +(A ·∇)B + B × (∇× A)+ A × (∇× B)
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                               16.       ∇× (A × B)= (B ·∇)A − B(∇· A) − (A ·∇)B + A(∇· B)
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                                                                                           2
                               17.                                             ∇· (∇f)= ∇ f
                               18.                                               ∇× (∇f)= 0
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                               19.                                             ∇· (∇× A)= 0
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                               20.                               ∇× (∇× A)= ∇(∇· A) −∇ A
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