Page 113 - Introduction to Colloid and Surface Chemistry
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Liquid-gas and liquid-liquid  interfaces  103

         substrate) and temperature  play an important part in determining the
         nature  of  the  film.  Monolayers  can  be  roughly  classified as:

         1.  Condensed  (solid) films, in which the  molecules are closely packed
           and  steeply orientated  towards  the  surface.
        2.  Films which are  still coherent  but occupy  a much larger  area  than
           condensed films. They  have no real three-dimensional equivalent,
           since they  act as highly compressible  liquids. A number of distinct
                                                         21
           types  of  these  expanded  films  have  been  recognised ,  the  most
           important  being  the  liquid-expanded  state,  but  these  will  not  be
           considered  in  detail.
        3.  Gaseous or  vapour films, in which the  molecules  are separate and
           move about  the surface independently, the surface pressure being
           exerted on the barriers containing the film by a series of collisions.

        Gaseous films

        The  principal  requirements  for  an  ideal  gaseous  film  are  that  the
        constituent  molecules  must  be  of  negligible  size  with  no  lateral
        adhesion  between  them.  Such  a  film  would  obey  an  ideal  two-
        dimensional  gas equation,  7r/4  =  kT,  i.e.  the  IT- A  curve would  be a
        rectangular  hyperbola.  This  ideal  state  of  affairs  is,  of  course,
        unrealisable  but  is approximated  to  by a  number of insoluble films,
        especially  at  high  areas  and  low  surface  pressures.  Monolayers  of
        soluble  material  are  normally  gaseous.  If  a  surfactant  solution  is
        sufficiently  dilute to allow solute-solute interactions  at the surface to
        be  neglected,  the  lowering  of  surface  tension  will  be approximately
        linear  with concentration  -  i.e.

            y -  y 0 -  be  (where b is a constant)

        Therefore

            TT  ~  be

        and  dy/dc  -  -b

        Substituting  in the  Gibbs  equation


                 kT  Ac
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