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                        3.9 STABILITY OF THE UNSTEADY EQUATION
                        Table 3.2: Function f c (ξ).                               May 25, 2005  10:54  65
                        Scheme           Range of ξ        f  c
                        Second-order     −∞ <ξ < ∞         ξ/2
                        UPWIND
                        QUICK [42]       −∞ <ξ < ∞         3/8 − ξ/4
                        HLPA [90]        ξ   [0, 1]        0
                                         ξ ∈ [0, 1]        ξ (1 − ξ)
                        Lin–Lin [43]     ξ   [0, 1]        0
                                         ξ ∈ [0, 0.3]      ξ
                                         ξ ∈ [0.3, 5/6]    3/8 − ξ /4
                                         ξ ∈ [5/6, 1]      1 − ξ



                        Thus, for positive P c , whereas UDS will always return   e =   P , the TVD scheme
                        returns different values of   e depending on the value of ξ (or shape of the local
                          profile). In fact, as the last expression shows, even a downwind value may be
                        returned. The TVD schemes thus typically switch among upwind, central-like, and
                        downwind (DDS) schemes.


                        3.9 Stability of the Unsteady Equation

                        We now consider the unsteady conduction–convection equation
                                                                       2
                                                   ∂T         ∂T      ∂ T
                                              ρ C p   + ρ C p u   = k    2  ,              (3.46)
                                                   ∂t          ∂x     ∂x
                                                                                               2
                        where all properties and u (positive) are constant. Now, let X = x/λ, τ = α t/λ ,
                        and P = u λ/α, where λ is an arbitrary length scale to be further defined shortly.
                        Then, Equation 3.46 will read as
                                                                  2
                                                   ∂T      ∂T    ∂ T
                                                      + P      =     .                     (3.47)
                                                   ∂τ      ∂ X   ∂ X 2


                        3.9.1 Exact Solution
                        If at t = 0, with T = T 0 sin (X ), the exact solution to Equation 3.47 is

                                              T = T 0 exp(−τ)sin(X − P τ).                 (3.48)

                        The solution represents a wave that moves P  τ to the right in each time interval
                         τ. The amplitude of the wave is T 0 exp(−τ). Thus, over a time interval  τ, the
                        amplitude ratio (or the amplitude decay factor) AR is given by

                                                T 0 exp [−(τ +  τ)]
                                          AR =                    = exp(− τ).              (3.49)
                                                    T 0 exp(−τ)
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