Page 139 - Introduction to Petroleum Engineering
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126                                             RESERVOIR GEOPHYSICS


              Answer
              A.  P‐wave acoustic impedance for upper layer

                                          kg     km        kg km
                         Z = (ρ V ) = 2800  m 3  ×30  s  = 8400  m 3  s
                                               .
                                 P
                           U
                                   U
                  and P‐wave acoustic impedance for lower layer
                                          kg     km        kg km
                         Z = (ρ V ) = 2600   ×28    = 7280
                                               .
                           L
                                 P L
                                          m 3     s       m 3  s
              b.  Reflection coefficient
                                  Z  − Z  7280  −8400
                             RC =  L   U  =          = 0 0714− .
                                  Z L  + Z U  7280  +8400



           7.3  SEISMIC RESOLuTION

           Seismic wave reflecting surfaces are due to changes in acoustic impedance between
           two  adjacent  media.  Seismic  resolution  is  the  ability  to  distinguish  between  two
           reflecting surfaces that are close together. The quality of seismic resolution depends
           on the orientation of the reflecting surfaces and interference effects, as we discuss in
           this section.

           7.3.1  Vertical Resolution

           Vertical resolution tells us how close two horizontal reflecting surfaces can be and still
           be separable. The two reflecting surfaces are the top and bottom of a thin layer. Maximum
           vertical resolution is expressed in terms of the dominant wavelength of a seismic wavelet
           λ , which is the ratio of wavelet velocity v to the dominant  frequency f :
            d                              i                     d
                                            v
                                       λ =  i  = vT                       (7.12)
                                        d
                                                id
                                            f d
           The dominant period T  is the inverse of dominant frequency f . As an illustration,
                                                              d
                              d
           suppose the wavelet velocity is 10 000 ft/s and the dominant period is 40 ms or 0.040 s,
           then the dominant frequency f  is 25 Hz and the dominant wavelength is 400 ft.
                                   d
              Maximum vertical resolution δz  is one fourth of the dominant wavelength λ :
                                       V                                   d
                                            λ    v
                                      δ z =  d  =  i                      (7.13)
                                        V
                                            4    f 4  d
           The maximum vertical resolution in the illustration earlier is approximately 100 ft.
           If the separation between two reflecting surfaces is less than the maximum vertical
           resolution, it is difficult or impossible to distinguish each of the reflecting surfaces.
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