Page 69 - Introduction to Transfer Phenomena in PEM Fuel Cells
P. 69

58     Introduction to Transfer Phenomena in PEM Fuel Cells
                           2.2.5. Effect of pressure
                             The preceding equations are valid for a pressure equal to the atmospheric
                           pressure. However, the battery can operate at different pressures, ranging
                           from atmospheric pressure to several bars [BAR 05, SPI 07]. For a process
                           considered isothermal, the change of free energy of Gibbs can be written as:
                                 dG = V ⋅ dP                                             [2.13]
                                       m
                           where:

                                                          3
                                                              –1
                             – V m is the molar volume, in [m .mol ];
                             – P is the pressure, in [Pa].
                             For an ideal gas, we write:

                                 PV =  RT                                                [2.14]
                                   m
                             Replacing equation [2.13] in [2.14], we find:


                                         dP
                                 dG =  RT                                                [2.15]
                                         P
                             Then, after integration:


                                                P 
                                      0
                                 G =  G + RTln                                         [2.16]
                                                P 0 
                                   0
                           where (G ) and (P 0) are respectively the Gibbs free energy and pressure at
                           standard pressure and temperature. During a chemical reaction of the
                           following type:

                                              +
                                 jA kB →   mC nD                                         [2.17]
                                   +
                             The change in Gibbs’ free energy is a function  of the products and
                           reactants, so that:

                                 Δ=   mG +   nG −  jG −  kG B                            [2.18]
                                  G
                                         C
                                                     A
                                               D
   64   65   66   67   68   69   70   71   72   73   74