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308  Chapter 12: Batch Reactors (BR)

                              To obtain the value of t for maximum  Pr, consider equation 12.3-22 with  fAl = 0,
                            fA2 = f*(t).  Then the equation may be written as


                                                        Pr = Kf*(t)l(t  + td)                 (12.3-32)

                            where K( = vccAoV) is a constant, and Pr is Pr(C). For maximum Pr,
                                                                              1
                                              dPr       0  + tddf,(tW)   -  f*(t)  =  o
                                              dt=               (t  + CA2

                            or


                                                     (t  +  t,,y   -  f*(t) = 0



                            Equation 12.3-33 is solved for  t,  and the result is used in equation 12.3-32 or its equiv-
                            alent to obtain the maximum value of Pr.






                            Consider a liquid-phase, first-order reaction A  +  C, occurring in a reactor of volume  V,
                            with a specified down-time,  td.  The reactor initially contains 5 moles of pure A. Determine
                            the reaction time which maximizes Pr(C), given kA = 0.021  mm’,  and  td = 30 min;
                            and calculate the maximum value of Pr(C).

       SOLUTION

                            Since this is a constant-density system, equation 12.3-33 applies. To use this, we require
                            f*(t).  From the rate law, and the material balance, equation 2.2-10,

                                                                                    dfA
                                          (-rA)   =  ~ACA   =  kAcA,(l   -  fA)   =  -2  =  cAo-
                                                                                     dt
                            From this.


                                                         g = k,(l - fA)


                            This integrates to
                                                          fA = 1 - &d                              (4


                            from which, in terms oft,
                                                          dfA   -  k +d                            (W
                                                          ~-
                                                           dt     A

                            Substituting the results from (A) and (B) in equation 12.3-33, we have

                                                   (t + t,)k,e-  kit  -  (1  -  e-kd)  =  0        ((2
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