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72  Chapter 4: Development of the Rate Law for a Simple System

                             and the following increases of pressure (AP) were noted (in part) with increasing time:

                                             tls      42   105  242   480   840   1440
                                             AP/kFa   4.5  9.9  17.9  25.9  32.5  37.9
                             From these results, determine the order of reaction, and calculate the value of the rate
                             constant in pressure units  (kFa)  and in concentration units (mol  L-l).


        SOLUTION

                             It can be shown that the experimental data given do not conform to the hypothesis of a
                             first-order reaction, by the test corresponding to that in Example 4-3. We then consider
                             the possibility of a second-order reaction. From equation 4.2-6, we write the combined
                             assumed form of the rate law and the material balance equation (for constant volume), in
                             terms of CHsCHO  (A), as

                                                     (  -rAp)  = -dp,ldt  = kApp;

                             The integrated form is

                                                           ’     ‘+kt
                                                          -    -   PAo   Ap
                                                          PA
                             so that l/PA  is a linear function of t. Values of PA can be calculated from each value of
                             AP, since  P, = pAo,  and

                                         AP = P -  P,  = PA  + PCH,  + Pco   -  PAo

                                             =  PA  +  2@,,   -  PA)  -  PAo =  PAo  -  PA =  48*4   -  PA  (3)
                             Values of  PA  calculated from equation (3) are:


                                             tls      42   105   242   480   840   1440
                                             pAlkPa  43.9  38.6  30.6  22.6  15.9  10.5


                               These values are plotted in Figure 4.2 and confirm a linear relation (i.e., n = 2). The
                             value of kAp  calculated from the slope of the line in Figure 4.2 is


                                                     k   = 5.07 X 10e5 kPa-’  s-l
                                                      AP
                             and, from equation 4.2-8 for kA in (-IA) = kAci,

                                        kA  = RTkAp  = 8.314(791)5.07  X 10m5  = 0.334 L  mole1  s-l

        4.3.3 Third-Order Reactions

                             The number of reactions that can be accurately described as third-order is relatively
                             small, and they can be grouped according to:

                               (1) Gas-phase reactions in which one reactant is nitric oxide, the other being oxygen
                                   or hydrogen or chlorine or bromine; these are discussed further below.
                               (2) Gas-phase recombination of two atoms or free radicals in which a third body
                                   is required, in each molecular act of recombination, to remove the energy of
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