Page 514 - Marine Structural Design
P. 514

490                                                   Part IY Structural Reliability

                 Considering S,,  A,  and K are random variables, the following safety check expression may be
                 defmed,

                                                                                    (27.33)
                         Ys
                 where the  subscript n refers to  the nominal  or design values. Reliability methods may be
                 applied to  calibrate the partial safety factors: stress factor  ys, damage safety factor yA and
                 material property safety factor yK . See Stahl and Banon (2002) for latest development on this
                 subject.


                 27.6  Numerical Examples
                 27.6.1  Example 27.1: Fatigue Reliability Based on Simple S-N Approach
                 Problem
                        Assuming that the fatigue strength is described by a S-N curve and the fatigue loads
                        are described by a Weibull distribution, then the fatigue damage can be obtained by
                        equation (27.7) given by

                        D=-.
                            K  (In No ),"
                        If only A, SO and K are considered as random variables, the failure probability may be
                        written as

                                                                                    (27.34)




                        g@)= X, -k- X;                                              (27.35)
                                    X,
                        and k is a constant.
                        Assuming m=3, k=106 and XI, X2 and X,  are independent and specified in Table 27.3.
                        Find the distribution of go and calculate failure probability directly using simple
                        approach.
                         Table 27.3  InDut Data








                 Solution
                        Before using FORM, it is shown that a simple approach can be applied to calculate Pf
                        in the case. The Eq. (27.5 1) can be rewritten as
   509   510   511   512   513   514   515   516   517   518   519