Page 288 - Marks Calculation for Machine Design
P. 288

P1: Shibu
                          January 4, 2005
                                      14:56
        Brown.cls
                 Brown˙C06
                                           STRENGTH OF MACHINES
                  270
                  where the units (MPa) have been dropped for the modulus of elasticity (E) in the square
                  root term as the critical stress (σ cr ) will also have units of (MPa). This is compatible with
                  the fact that the secant can only be evaluated for a nondimensional quantity.
                    As the critical stress (σ cr ) is on both sides of Eq. (6.36) it must be solved by trial and
                  error or some other numerical method. To show how quickly the trial-and-error method can
                  obtain a reasonably accurate value for the critical stress, start with an educated guess for
                  the critical stress, then modify this guess in successive iterations until the guess equals the
                  right hand side of Eq. (6.36). Stop when an appropriate level of accuracy is reached.
                    An excellent educated guess would be the yield stress divided by two, which would be
                  135 MPa. Substitute this value into the right hand side of Eq. (6.36) to give
                                     270 MPa
                          σ cr =            √
                               1 + (1.6) s (0.15) σ cr
                                     270 MPa           270 MPa      270 MPa
                          135 =             √     =              =
                               1 + (1.6) s[(0.15) 135]  1 + (1.6) s [1.74]  1 + (−9.3)
                               270 MPa
                             =        =−32.4
                                −8.3
                    As the right hand side came out negative, try a new guess of 70.
                                     270 MPa
                          σ cr =             √
                                1 + (1.6) s (0.15) σ cr
                                     270 MPa           270 MPa     270 MPa
                           70 =              √   =               =
                                1 + (1.6) s[(0.15) 70]  1 + (1.6) s [1.25]  1 + (5.15)
                                270 MPa
                             =         = 43.9
                                 6.15
                    Split the difference between 70 and 43.9 and try 57.
                                     270 MPa
                          σ cr =             √
                               1 + (1.6) s (0.15) σ cr
                                     270 MPa           270 MPa      270 MPa
                           57 =              √    =              =
                               1 + (1.6) s (0.15) 57  1 + (1.6) s [1.13]  1 + (3.77)
                               270 MPa
                             =         = 56.6 = σ cr
                                 4.77
                    Notice that it required only three iterations, compared to four iterations for the U.S.
                  Customary calculation, to get one decimal place accuracy for the critical stress. Also, this
                  value of the critical stress would still predict a safe design.


                  6.2.4 Short Columns
                  The big question is how short is short? The machine element could be so short that it can
                  be considered as a pure compression member, where failure is a shortening of the column
                  at the yield stress (S y ).
                    For columns having slenderness ratios between for pure compression and for one
                  which would mean that the secant formula would apply, the critical stress (σ cr )
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