Page 302 - Marks Calculation for Machine Design
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P1: Shashi
                                      15:4
                          January 4, 2005
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                  and the coefficients (a) and (b), both dimensionless, are given in Eq. (7.18) as
                                         1  STRENGTH OF MACHINES  1
                                                         1
                                     a =      and   b =−   log                 (7.18)
                                        K f              3    K f
                  where the reduced stress concentration factor (K f ) is found from Eq. (6.23).
                    Consider the following example that brings together all the modifying factors in the
                  Marin equation for a particular machine element.
                            U.S. Customary                       SI/Metric
                  Example 2. Determine the endurance limit  Example 2. Determine the endurance limit
                  (S e ) using the Marin equation for a 1.0-in di-  (S e ) using the Marin equation for a 25-mm di-
                  ameter machined shaft with a transverse hole  ameter machined shaft with a transverse hole
                  under reversed bending at room temperature,  under reversed bending at room temperature,
                  where                              where
                    S ut = 120 kpsi                    S ut = 840 MPa
                    S y = 80 kpsi                      S y = 560 MPa
                    K t = 2.15 (0.125-in transverse hole)  K t = 2.15 (3.2-mm transverse hole)
                     q = 0.8 (notch sensitivity)        q = 0.8 (notch sensitivity)
                  solution                           solution
                  Step 1. Using Eq. (7.8) and values for the  Step 1. Using Eq. (7.8) and values for the
                  coefficient (a) and exponent (b) from Table 7.1,  coefficient (a) and exponent (b) from Table 7.1,
                  calculate the surface finish factor (k a ) as  calculate the surface finish factor (k a ) as
                      k a = aS ut b                      k a = aS ut b
                         = (2.70 kpsi)(120 kpsi) −0.265    = (4.51 MPa)(840 MPa) −0.265
                         = (2.70)(0.2812)                  = (4.51)(0.1679)
                         = 0.76                            = 0.76
                  Step 2. Using Eq. (7.10) calculate the size  Step 2. Using Eq. (7.10) calculate the size
                  factor (k b ) as                   factor (k b ) as
                               −0.1133    −0.1133                −0.1133     −0.1133
                           d          1                      d           25

                     k b =        =                    k b =         =
                          0.3        0.3                    7.62        7.62
                       = (3.33) −0.1133  = 0.87          = (3.28) −0.1133  = 0.87
                  Step 3. As the shaft is bending, the load type  Step 3. As the shaft is bending, the load type
                  factor (k c ) from Eq. (7.14) is   factor (k c ) from Eq. (7.14) is
                               k c = 1                           k c = 1
                  Step 4. As the shaft is operating at room  Step 4. As the shaft is operating at room
                  temperature, the temperature factor (k d ) from  temperature, the temperature factor (k d ) from
                  Eq. (7.15) and Table 7.2 is        Eq. (7.15) and Table 7.2 is
                              k d = 1                            k d = 1
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