Page 363 - Marks Calculation for Machine Design
P. 363

P1: Sanjay
                          January 4, 2005
                                      15:14
        Brown.cls
                 Brown˙C08
                              U.S. Customary  MACHINE ASSEMBLY    SI/Metric       345
                    Step 10. Substitute the middle stiffness  Step 10. Substitute the middle stiffness
                    (k middle ) found in step 7, the stiffness (k 1 ) found  (k middle ) found in step 7, the stiffness (k 1 ) found
                    in step 8, and the stiffness (k 2 ) found in step 9  in step 8, and the stiffness (k 2 ) found in step 9
                    in Eq. (8.18) to determine the overall stiffness  in Eq. (8.18) to determine the overall stiffness
                    of the members (k members ) as     of the members (k members ) as
                          1     1   1    1                  1      1  1     1
                              =   +   +                         =   +   +
                        k members  k 1  k 2  k middle     k members  k 1  k 2  k middle
                                     1                                 1
                              =       7                         =        9
                                4.49 × 10 lb/in                   7.88 × 10 N/m
                                      1                                  1
                                +                                 +
                                        7
                                                                          9
                                 3.26 × 10 lb/in                    5.80 × 10 N/m
                                      1                                  1
                                +                                 +
                                        8
                                 1.73 × 10 lb/in                    3.26 × 10 10  N/m
                                 2.23 × 10                          1.27 × 10
                                       −8                              −10  
                                             in                                 m
                              =  + 3.07 × 10  −8              =  + 1.72 × 10  −10 
                                 + 5.78 × 10 −9  lb                 + 3.07 × 10 −11  N
                           1            −8                    1           −10
                               = 5.873 × 10  in/lb               = 3.300 × 10  m/N
                         k members                         k members
                    Therefore,                         Therefore,
                                      1                                  1
                         k members =                       k members =
                                 5.873 × 10 −8  in/lb              3.300 × 10 −10  m/N
                                       7
                                                                         9
                              = 1.70 × 10 lb/in                  = 3.03 × 10 N/m
                              = 17,000 kips/in                   = 3,030 MN/m
                    Step 11. Substitute the stiffness of the cap  Step 11. Substitute the stiffness of the cap
                    screw (k T ) from step 2 and the stiffness of  screw (k T ) from step 2 and the stiffness of
                    the members (k members ) found in step 10 in  the members (k members ) found in step 10 in
                    Eq. (8.35) to determine the joint constant (C) as  Eq. (8.35) to determine the joint constant (C) as
                             k cap screw                         k cap screw
                      C =                                C =
                          k cap screw + k members            k cap screw + k members
                                                                        9
                                      6
                               6.38 × 10 lb/in                    1.20 × 10 N/m
                        =        6         6               =        9        9
                          (6.38 × 10 + 17.00 × 10 ) lb/in    (1.20 × 10 + 3.03 × 10 ) N/m
                                 6
                                                                   9
                          6.38 × 10 lb/in                    1.20 × 10 N/m
                        =                                  =
                                                                   9
                                 6
                          23.38 × 10 lb/in                   4.23 × 10 N/m
                        = 0.27                             = 0.28
                    Step 12. Use the given proof strength (S proof )  Step 12. Use the given proof strength (S proof )
                    and tensile-stress area (A T ) in Eq. (8.25) to  and tensile-stress area (A T ) in Eq. (8.25) to
                    determine the proof load (F proof )  determine the proof load (F proof )
                    F proof = S proof A T              F proof = S proof A T
                                                                    6
                                                                        2
                                3
                                    2
                                                                                   2
                                                2
                         = (85 × 10 lb/in )(2.26 × 10 −1  in )  = (600 × 10 N/m )(1.57 × 10 −4 m )
                         = 19,200 lb                       = 94,200 N
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