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2.5 Nonhomogeneous Systems                                                          69

                                        Now turn to the question, “When does a consistent system have a unique
                                    solution?” It is known from (2.5.7) that the general solution of a consistent
                                    m × n nonhomogeneous system [A|b] with rank (A)= r is given by


                                                                                    h n−r ,
                                                    x = p + x f 1  h 1 + x f 2  h 2 + ··· + x f n−r
                                    where

                                                        x f 1  h 1 + x f 2  h 2 + ··· + x f n−r  h n−r
                                    is the general solution of the associated homogeneous system. Consequently, it
                                    is evident that the nonhomogeneous system [A|b] will have a unique solution
                                    (namely, p ) if and only if there are no free variables—i.e., if and only if r = n
                                    (= number of unknowns)—this is equivalent to saying that the associated ho-
                                    mogeneous system [A|0] has only the trivial solution.
                   Example 2.5.2

                                    Consider the following nonhomogeneous system:

                                                             2x 1 +4x 2 +6x 3 =2,
                                                              x 1 +2x 2 +3x 3 =1,
                                                              x 1    + x 3 = −3,
                                                                           =8.
                                                             2x 1 +4x 2
                                    Reducing [A|b]to E [A|b] yields

                                                    246          2        100        −2
                                                                                     
                                                   123          1      010          3 
                                                    101        −3         001        −1
                                           [A|b]=                 −→                  = E [A|b] .
                                                    240          8        000          0
                                    The system is consistent because the last column is nonbasic. There are several
                                    ways to see that the system has a unique solution. Notice that

                                                      rank (A) = 3 = number of unknowns,

                                    which is the same as observing that there are no free variables. Furthermore,
                                    the associated homogeneous system clearly has only the trivial solution. Finally,
                                    because we completely reduced [A|b]to E [A|b] , it is obvious that there is only
                                                                                   
                                                                                 −2
                                    one solution possible and that it is given by p =    3    .
                                                                                 −1
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