Page 475 - Mechanical Engineers' Handbook (Volume 2)
P. 475

466   Closed-Loop Control System Analysis

                                                        h(kT)   ƒ(kT)
                          Hence Eq. (46) can be written as
                                                       n
                                          h(kT    )   a     a    n 1          a     ƒ(kT)     (47)
                                                     n     n 1           1
                          If an nth-order polynomial as in Eq. (47) is used to extrapolate the data, then the hold circuit
                          is called an nth-order hold. If n   1, it is called a first-order hold (the nth-order hold uses
                          the past n   1 discrete data ƒ[(k   n)T]). The simplest data hold is obtained when n   0
                          in Eq. (47), that is, when
                                                      h(kT    )   ƒ(kT)                       (48)
                          where 0       T and k   0, 1, 2,.... Equation (48) implies that the circuit holds the
                          amplitude of the sample from one sampling instant to the next. Such a data hold is called a
                          zero-order hold. The output of the zero-order hold is shown in Fig. 17.

                          Zero-Order Hold
                          Assuming that the sampled signal is 0 for k   0, the output h(t) can be related to ƒ(t)as
                          follows:
                                     h(t)   ƒ(0)[u (t)   u (t   T)]   ƒ(T)[u (t   T)   u (t   2T)]
                                               s
                                                     s
                                                                    s
                                                                              s
                                             ƒ(2T)[u (t   2T)]   u (t   3T)]
                                                   s
                                                              s
                                              ƒ(kT){u (t   kT)   u [t   (k   1)T]}            (49)

                                           k 0      s         s
                          Since L u (t   kT)    e  kTs /s, the Laplace transform of Eq. (49) becomes
                                 s
                                             L[h(t)]   H(s)      ƒ(kT)  e  kTs    e  (k 1)Ts

                                                           k 0          s

                                                     1   e  Ts
                                                               ƒ(kT)e  kTs                    (50)
                                                       s    k 0
                          The right-hand side of Eq. (50) may be written as the product of two terms:
                                                      H(s)   G (s)F*(s)                       (51)
                                                              h0



















                                        Figure 17 Input ƒ(kt) and output h(t) of the zero-order hold.
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