Page 114 - Modeling of Chemical Kinetics and Reactor Design
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84    Modeling of Chemical Kinetics and Reactor Design

                              and

                                             T  ∆C
                                 ∆S =  ∆S +  ∫    p  dT
                                         o
                                   o
                                         s      T
                                             Ts
                              Hence,


                                                                                cal
                                 ∆C =−15 455  +17 124  ×10 −3 T − 4 887 ×10 −6 T 2
                                                                .
                                                  .
                                          .
                                    p
                                                                             mol K N
                                                                                     2
                              and
                                   o
                                 ∆S = ( 2 4610.  ) − 4587 3.  − (31 29.  )
                                   s
                                                cal
                                           .
                                     =− 47 54
                                              mol K
                                                  •
                              This is the entropy change for a complete conversion to NH  where
                                                                                       3
                              1 kmol of N  is converted. The entropy change at 428 K is:
                                          2

                                               428  −15 455
                                                                                      
                                                      .
                                   o
                                                                           .
                                                              .
                                          .
                                 ∆S =− 47 54 +  ∫       +17 124  ×10 −3  − 4 887  ×10 −6 TdT
                                                                                      
                                               298    T
                                               428                                       T 2 
                                                                         −3
                                                                 .
                                                      .
                                     =− 47 54 +   −15 455ln T  +17 124  ×10 T  − 4 887 ×10 −6  
                                          .
                                                                               .
                                               298                                       2  
                                                          428           −3
                                     =−47 54  + −15 455ln      +17 124  ×10  (428 − 298 )
                                                                  .
                                              [
                                                   .
                                          .
                                                          298 
                                                              )
                                         .
                                      −  4 887  ×10 −6  (428 2  −298 ]
                                                             2
                                             2
                                                    +
                                             −
                                     =− 47 54 5 595 2 226  − 0 231
                                          .
                                                .
                                                       .
                                                              .
                                                cal
                                     =− 51 14
                                          .
                                             molK N  2
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