Page 109 - Modeling of Chemical Kinetics and Reactor Design
P. 109

Thermodynamics of Chemical Reactions   79

                                If no phase change occurs, the difference ∆H products  – ∆H reactants  can
                              be written as


                                                        T
                                 ∆H       −  ∆H      =  ∫  ∆C dT
                                    products   reactants     p                          (2-102)
                                                       298

                              where C  is given by
                                      p

                                 ∆C =  ∆a +( ∆b T) + ( ∆c T ) + ( ∆d T )                (2-103)
                                                                     3
                                                           2
                                                                   •
                                               •
                                                        •
                                    p
                              and ∆C  is in cal/mol K, J/mol K, using T in degrees Kelvin.
                                     p
                                The constants for the equation are found by
                                 ∆a =  ∑ α products  a •  products  −  ∑ α reactants  a •  reactants  (2-104)
                                 ∆b=  ∑ α products  b •  products ∑ α reactants  b •  reactants  (2-105)
                                                        −

                                 ∆c=  ∑ α products  c •  products ∑ α reactants  c •  reactants  (2-106)
                                                        −

                                                        −
                                 ∆d =  ∑ α products  d •  products ∑ α reactants  d •  reactants  (2-107)

                              So that

                                 T           T
                                 ∫  ∆CdT =   ∫ { ∆a +( ∆b T)+( ∆c T ) +( ∆d T )} dT     (2-108)
                                                                  2
                                                                            3
                                                                          •
                                                                •
                                                       •
                                      p
                                 298        298
                                Integrating Equation 2-108 yields
                                 T                       ∆b
                                               (
                                 ∫  ∆CdT =  ∆a T − 298 )+ (  T −298 2 )
                                                              2
                                      p
                                 298                      2
                                                                                        (2-109)
                                                             ∆d
                                              ∆c
                                                  3
                                                                  4
                                                      + ( T −298 3 ) + ( T −298 4 )
                                              3              4
                                The heat of reaction at the system temperature is therefore given by
   104   105   106   107   108   109   110   111   112   113   114