Page 307 - Modeling of Chemical Kinetics and Reactor Design
P. 307

Introduction to Reactor Design Fundamentals for Ideal Systems  277

                                 N =2 N    X                                             (5-49)
                                  B     AO  A
                                ε  is the fractional change in volume of the system between no
                                 A
                              conversion and complete conversion of reactant A given by


                                     V X A =1  −  V X A =0
                                 ε =                                                     (5-20)
                                  A
                                         V X A =0
                                For the gas phase reaction A → 2B, ε  = (2 – 1)/1 =1 or
                                                                    A

                                V= V (1 + ε X )                                          (5-18)
                                      O     A  A
                                Since two moles of B are formed for every mole of  A that dis-
                              appears, then the mole balance table becomes


                                                      Mole initially
                              Component               at time t = 0             Moles at t = t
                              A                            N                    N  = N  (1 –X )
                                                            AO                   A    AO    A
                              B                             0                       2N  X
                                                                                      AO  A
                              Total moles                  N                      N  (1 + X )
                                                            AO                     AO     A
                              Volume                       V                      V (1 + X )
                                                             O                      O     A
                              The batch reactor design equation for component A is



                                 − ( r A )=−  1  dN A  = kC 2 A                          (5-50)
                                         V dt

                                Substituting Equations 5-9, 5-10, and 5-18 into Equation 5-50 yields


                                                           N
                                                                       
                                 − ( r  )=  N AO   dX A  =   AO  − (1  X A )  2
                                                         k
                                   A                                                     (5-51)
                                       V O (1  + X A ) dt   V O  (1  + X A ) 
                                                           
                                                                       
                                Rearranging Equation 5-51 gives
                                 1+ (  X A )dX A  N AO

                                   1− (  X A ) 2  = k  V O  dt                           (5-52)
   302   303   304   305   306   307   308   309   310   311   312