Page 66 - Modeling of Chemical Kinetics and Reactor Design
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36    Modeling of Chemical Kinetics and Reactor Design

                                Using the steady state approximation,
                                ( +r CH CO * ) net  = 0  and ( +r CH 3 * ) net  = 0

                                     3

                                The overall rate equation is:


                                                      3
                                 − ( r    )  =−  dC CH CHO
                                   CH CHO  net       dt
                                     3
                                                                                        (1-150)
                                             = kC         + k C    C
                                                1  CH CHO    2  CH 3 *  CH CHO
                                                                       3
                                                     3
                                From Equations 1-148 and 1-149,  2kC  2   =  k C       and
                                                                    4  CH * 3  1  CH 3 CHO
                                          k          05 .
                                 C  *  =    1  C CH CHO                               (1-151)
                                  CH 3    2 k 4  3  

                                Substituting Equation 1-151 into Equation 1-150 gives


                                              dC CH CHO
                                 − ( r CH CHO ) = –  3
                                     3
                                                  dt
                                                            k 1           05 .        (1-152)
                                           = kC CH CHO  + k 2   2  4  • C CH CHO    C CH CHO
                                              1
                                                  3
                                                                                3
                                                            k
                                                                     3
                                       k          05 .
                                If  k 2  1  C CH CHO  >>  k C CH CHO , then Equation 1-152 becomes
                                                          1
                                       2 k 4  3              3

                                               dC CH CHO
                                 − ( r    ) =−      3
                                   CH CHO          dt
                                     3
                              and


                                                          2
                                  dC          dC        kk   05 .
                                 −   CH CHO  =   CH 4  =    2  1   C 32               (1-153)
                                       3
                                                                  CH CHO
                                      dt         dt     2 k 4      3
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