Page 70 - Modeling of Chemical Kinetics and Reactor Design
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40    Modeling of Chemical Kinetics and Reactor Design


                                                                2
                                 − ( r  )  = k C  C    +  k 2  •  C CH 4  • C  k C
                                   H 2      1  CH 4  H 2              H  *  3  H 2
                                               2
                                      net                k 3  C H 2
                                                                                        (1-168)
                                         = kC CH 4 C  H 2  + k C C H 4 C H *
                                                          2
                                            1
                                               2
                                                             2
                                The overall rate of reaction of  C   is
                                                                 2
                                                                CH 4
                                        )
                                 − ( r     = k C    C    + k C    C                     (1-169)
                                    2
                                                 2
                                                               2
                                   CH 4  net  1  CH 4  H 2  2  C H 4  H *
                                        r − (  CH )  −  k C  C
                                                        2
                                 C   =    2  4  net  1  CH 4  H 2                       (1-170)
                                  H *         kC  CH 4
                                                2
                                                   2
                                Substituting Equation 1-170 into Equation 1-168 yields
                                      )                            − ( r CH 4 ) net  − k C CH 4  C  H 2  
                                                                 
                                                                                          
                                                                                1
                                                                                   2
                                                                      2
                                 − ( r   = k C    C    + k C                             
                                   H 2      1  CH 4  H 2  2  C H 4
                                                             2
                                               2
                                      net                                 kC
                                                                          2  CH 4        
                                                                                          
                                                                 
                                                                               2
                                         = kC     C    + − ( r  )  − kC     C
                                            1  CH 4  H 2   C H 4  net  1  CH 4  H 2
                                                                         2
                                                            2
                                               2
                                 − ( r  )  =− ( r  )                                    (1-171)
                                   H 2        CH 4
                                               2
                                      net          net
                                 − ( r  )  =− ( r  )  = k C    C   + k C     C  *       (1-172)
                                   H 2        CH 4      1  CH 4  H 2  2  C H 4  H
                                               2
                                                                          2
                                                            2
                                      net          net
                              but
                                             2
                                 C  *  =  k 3  •  C CH 5 *  C H 2
                                  H    k 2   C CH 4
                                               2
                                                        )
                              Since  (+r  * net  and  (+r  * net  are zero
                                           )
                                        2
                                       CH 5           H
                                 kC     C   +  k C   C   −  k C   C   −  k C   C   =  0  (1-173)
                                  1  CH 4  H 2  2  C H 4  H *  3  C H 5 *  H 2  4  CH 5 *  H  *
                                     2
                                                  2
                                                                            2
                                                               2
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