Page 69 - Modeling of Chemical Kinetics and Reactor Design
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Reaction Mechanisms and Rate Expressions  39
                                ( +r  * )  = k C  CH 4  C H 2  + k C  C H 4  C H *  − k C  *  C  H 2
                                              1
                                                                          3
                                                            2
                                                                2
                                                 2
                                   CH 5
                                                                             2
                                                                            C H 5
                                    2
                                        net
                                                                                        (1-162)
                                               − kC  *  C  *
                                                4
                                                  CH 5  H
                                                   2
                                The overall rate of reaction of C  is
                                                               H*
                                ( +r  )  = k C    C    + k C    C    − k C    C
                                               2
                                                                           2
                                   H ∗  net  1  CH 4  H 2  3  CH 5 *  H 2  2  C H 4  H ∗
                                                             2
                                                                                        (1-163)
                                            − kC   * C  *
                                              4
                                                 2
                                                CH 5  H
                                The overall rate of reaction of  C  is
                                                                H 2
                                 − ( r  )  = k C   C   + k C     C                      (1-164)
                                   H 2      1  CH 4  H 2   3    *  H 2
                                                2
                                      net                    CH 5
                                                              2
                                                                   )
                                                      )
                                Assuming that   (+r  * net  and  (+r  * net  are zero, equating Equa-
                                                   2
                                                  CH 5           H
                              tions 1-162 and 1-163 gives:
                                 kC CH 4  C  H 2  +  k C C H 4  C H *  −  k C  C H 5 * C  H 2  −  k C  CH 5 * C H *
                                                                           4
                                  1
                                               2
                                                             3
                                                   2
                                     2
                                                                              2
                                                                2
                                                                                        (1-165)
                                 = k C    C   + k C    C    − k C    C   − k C    C
                                   1  CH 4  H 2  3  CH 5 *  H 2  2  C H 4  H  *  4  C H 5 *  H *
                                                                  2
                                       2
                                                                                2
                                                    2
                              Therefore,
                                 2kC CH  4  C H *  =  2 k C C 2 H * 5  C H  2           (1-166)
                                   2
                                                   3
                                       2
                                 kC CH 4  =  C  CH 5 *
                                  2
                                              2
                                      2
                                  kC         C                                          (1-167)
                                   3  H 2     H  *
                                From Equation 1-164
                                      )
                                 − ( r   = k C    C    + k C     C
                                               2
                                   H 2      1  CH 4  H 2  3     *  H 2
                                      net                    CH 5
                                                              2
                                Substituting Equation 1-167 into Equation 1-164 gives
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