Page 71 - Modeling of Chemical Kinetics and Reactor Design
P. 71

Reaction Mechanisms and Rate Expressions  41

                                 kC     C   − k C    C   +  k C   C   −  k C   C    =  0 (1-174)
                                  1  CH 4  H 2  2  C H 4  H *  3  C H 5 *  H 2  4  CH 5 *  H  *
                                     2
                                                  2
                                                                            2
                                                               2
                              Adding Equations 1-173 and 1-174 gives
                                 2kC  2  4  C H 2  −  2k C CH * 5 C H *  =  0           (1-175)
                                   1 CH
                                                  4
                                                      2
                              Subtracting Equations 1-173 from Equation 1-174 yields

                                 2kC      C   −  2k C   C   =  0
                                   2  CH 4  H  *  3  C 2 H  * 5  H 2                    (1-176)
                                       2
                                 kC CH 4  C  H 2  =  k C CH 5 *  C H *                  (1-177)
                                                4
                                  1
                                     2
                                                    2
                              and
                                 kC     C    =  k C    C
                                  2  CH 4  H  *  3  C H 5 *  H 2                        (1-178)
                                     2
                                                    2
                              From Equation 1-177

                                         kC      C
                                          1
                                              2
                                 C   *  =    CH 4  H 2                                  (1-179)
                                   2
                                  CH 5      kC  H *
                                             4
                                Substituting Equation 1-179 into Equation 1-178 gives
                                                        kC     C
                                                         1
                                                            2
                                 kC CH 4 C H *  =  k • C H 2  •  CH 4  H 2
                                  2
                                                3
                                     2
                                                          kC
                                                            4  H  *
                              Therefore,
                                 C 2  *  =  k 3  •  k 1  C 2
                                  H   k   k    H 2
                                        2   4

                              where


                                 K =  k 3  •  k 1
                                    k   k
                                      2  4
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